I Think You Plug in the X And Y Axis And You Will Get It
We are comparing maxima. From the graph we know that the max of one graph is +2 at x = -2. What about the other graph? Need to find the vertex to find the max.
Complete the square of <span>h(x) = -x^2 + 4x - 2:
</span>h(x) = -x^2 + 4x - 2 = -(x^2 - 4x) -2
= -(x^2 - 4x + 4 - 4) - 2
=-(x^2 - 4x + 4) -2+4
= -(x-2)^2 + 2 The equation describing this parabola is y=-(x-2)^2 + 2, from which we know that the maximum value is 2, reached when x = 2.
The 2 graphs have the same max, one at x = -2 and one at x = + 2.
Let's take a look. A baker is using three cups of water for every eight ounces of water.
Let's think of a ratio!
8 * x = 96
x = cups of flour.
Let's solve the equation.
96 divided by 8 equals 12.
The correct answer would be D - 12 cups of flour.
“A” is the answer; “B” is not correct/equivalent to the given equation, “C” is not simplified enough, and “D” is in slope-intercept form
