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2 years ago

14

A Joule, witch is a unit of work, is equal to (A) a newton divided by a meter (B) a newton divided by a second (C) a newton ti

mes a second (D) a newton times a meter

1 answer:

mr Goodwill [35]2 years ago

5 0

The answer is D hope this help's.

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Which element in the third period would you expect to have the larger atomic radius, sodium (Na) or Sulfur (S)?

jeyben [28]

<u>Answer: </u>The correct answer is Option B.

<u>Explanation:</u>

The given elements that is sodium and sulfur are the elements which belong to the same period that is third period.

As, the electrons are added up to the same shell across a period, the number of protons also increase and hence, they attract the electrons more effectively. This means that the effective nuclear charge also increases and the size of the sulfur thus shrink and hence, the size (atomic radius) of sodium is the largest amongst third period.

Therefore, the correct answer is Option B.

7 0

2 years ago

Read 2 more answers

What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial

beks73 [17]

Answer:

0.02405 g/L is the solubility of argon in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{Ar}=K_H\times p_{gas}$

where,

$K_H$ = Henry's constant = $1.40\times 10^{-3}mol/L.atm$

$p_{Ar}$ = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

$C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L$

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

$6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L$

0.02405 g/L is the solubility of argon in water at 25 °C.

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3 years ago

In a given substance, as the temperature of a substance increases, the volume of that substance

steposvetlana [31]

C. Increases. Increasing temperature=Increasing Volume

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2 years ago

Balance each of these equations.

mafiozo [28]

The answer I would choose is the third one

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2 years ago

. What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)?

erica [24]

Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0

<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>

6 0

3 years ago