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3 years ago

Can you imagine a situation in which the reserve of a fuel might be increased?

2 answers:

6 0

The reserve of a fossil fuel might be increased if mining or extraction techniques improve so that more of fuel can be extracted for a profit

hammer [34]3 years ago

6 0

The reserve of a fossil fuel could be increased if mining or the extraction techniques of removing fossil fuels improve so that more of fuel can be extracted for more profit.

You might be interested in

Which scientific investigation describes a field study?

weqwewe [10]

Answer:

A. A scientist investigates a mouse's growth in nature by watching the animal.

A field study is a raw collection of data, typically in the natural habit of the organism; hence why an experiment taken in a lab isn't a field study.

7 0

3 years ago

Which type of radioactive particle was emitted by the following isotopes?

Paul [167]

Radioactive decay or disintegration is a process through which unstable nuclei form q more stable nuclei by the release of elementary particles like alpha particles, beta, protons, neutrons etc along with the release of energy.

In the given examples:

a) N-13 will get converted in to carbon, C-12 along with the release of a proton as shown below:

₇N¹³ → ₆C¹² + ₁H¹

b) N-15 will get converted in to boron B-11 along with the release of an alpha particle

₇N¹⁵ → ₅B¹¹ + ₂He⁴

3 0

4 years ago

Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty

anastassius [24]

Answer :

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression of $HC_2H_3O_2$ will be:

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression of $Co(H_2O)_6^{3+}$ will be:

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression of $CH_3NH_3^+$ will be:

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

3 0

3 years ago

Write the chemical formula for:

docker41 [41]

Lead (IV) nitrate + sodium sulfate lead(IV) sulfate + sodium nitrate
Pb(NO3)4 (aq) + 2 Na2SO4 (aq) Pb(SO4)2 (s) + 4 NaNO3 (aq)
I think this is what you are looking for. If not I am sorry.

6 0

3 years ago

Which of the following solutions will behave closest to an ideal solution?

puteri [66]

The science part because the science is particularly of science

6 0

4 years ago