Answer:
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The empirical formula of the compound is C4H1.
An empirical formula represents the whole number ratio of various atoms present in a compound.
If the mass percent of various elements present in a compound is known, its empirical formula can be determined
We are given that a compound contains 4 mole C and 1 mole H.
Hence, the ratio of C: H is 4:1, which is already in the form of the simplest whole number.
Therefore, the empirical formula of the given compound is C4H1 and its molecular mass is 12 x 4 + 1 = 49.
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They are arranged in shells
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of HCl to MgCl₂ is 2:1
we have been told that Mg is in excess therefore HCl is the limiting reactant
number of HCl moles reacted - 0.100 mol/L x 0.0256 L = 0.00256 mol
according to molar ratio, number of MgCl₂ moles formed - 0.00256/2
Therefore number of MgCl₂ moles formed - 0.00128 mol
mass of MgCl formed - 0.00128 mol x 95.20 g/mol = 0.122 g
