Question

A very long straight wire has charge per unit length 1.56×10−10 C/m .

Answer 1

Answer:

The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.

Explanation:

using Guass law,

(guessing that a cylinder of radius r and length L around wire such that wire is at centre )

E. A = qin / e0

E ( 2πr L ) = (1.56 x $10^{-10}$ x L) / (8.85 x $10^{-12}$)

E = (1.56 x $10^{-10}$ ) / (2πr x 8.85 x  $10^{-12}$)

so 2.40 = (1.54 x $10^{-10}$ ) / (2πr x 8.85 x $10^{-12}$)

2.40 (6.284r) = 0.174 x 10²

15.0816r = 17.4

r = 1.1537m