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bogdanovich [222]
2 years ago
11

8. in a hall experiment, a current of 25 a is passed through a long foil of ag, which is 0.1 mm thick and 3mm long. calculate th

e hall voltage produces across the width by a flux of 1.4 w/m2. if the conduction of ag is 6.8x10mho/m. estimate the mobility and hall coefficient.
Physics
1 answer:
pashok25 [27]2 years ago
8 0

The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

<h3>What is electric current?</h3>

Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.

Given data;

Electric current,I= 25 A

Thickness  = 0.1 mm

Length = 3 mm

Flux  = 1.4 w/m²

The charge density is found as;

\rm \rho  =-  \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3

The value of the hall voltage is;

\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v

The mobility of electrons is;

\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}

Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

To learn more about the electric current refer to the link;

brainly.com/question/2264542

#SPJ1

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One of the key disadvantages of buying fitness equipment is __________. A. privacy B. flexibility C. maintenance D. choice Pleas
Alex Ar [27]

Answer:

<h2>C. maintenance </h2>

Explanation:

I personally believe one key disadvantages is the cost of maintaining the equipment unlike the gym where you have to subscribe for the month or the year and forget about anything, owning the gym equipment comes with the extra cost and responsibilities of maintenance to the owners.

5 0
3 years ago
Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated
Artemon [7]

Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

<h3>What is Newton's law of gravitation?</h3>
  • Gravitation is the force of attraction between any two bodies.
  • Every body in the universe attracts every other body with a force.
  • This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.
  • Mathematically we can expressed it as,

                        F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2

<h3>How to solve the problem?</h3>
  • Here, we have given with the data's,

                      M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m

  • Thus, the force of attraction between these two bodies will be,

               F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

Learn more about the Newton's law of gravitation here:

brainly.com/question/28045318

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6 0
2 years ago
A plastic rod 1.3 m long is rubbed all over with wool, and acquires a charge of -3e-08 coulombs. we choose the center of the rod
Anestetic [448]
(a) The plastic rod has a length of L=1.3m. If we divide by 8, we get the length of each piece:
L/8=1.3m/8=0.1625 m

(b) The center of the rod is located at x=0. This means we have 4 pieces of the rod on the negative side of x-axis, and 4 pieces on the positive side. So, starting from x=0 and going towards positive direction, we have: piece 5, piece 6, piece 7 and piece 8. Each piece is 0.1625 m long. Therefore, the center of piece 5 is at 0.1625m/2=0.0812 m. And the center of piece 6 will be shifted by 0.1625m with respect to this:
c_6 = 0.0812m+0.1625m=0.2437 m

(c) The total charge is Q=-3 \cdot 10^{-8}C. To get the charge on each piece, we should divide this value by 8, the number of pieces:
Q/8=-3\cdot 10^{-8}C/8=-3.75\cdot 10^{-9}C

(d) We have to calculate the electric field at x=0.7 generated by piece 6. The charge on piece 6 is the value calculated at point (c):
q= -3.75\cdot 10^{-9}C
If we approximate piece 6 as a single  charge, the electric field is given by
E=k_e  \frac{q}{d^2}
where k_e=8.99\cdot 10^9Nm^2C^{-2} and d is the distance between the charge (center of piece 6, located at 0.2437m) and point a (located at x=0.7m). Therefore we have
E= 8.99\cdot 10^9 Nm^2C^{-2} \frac{-3.75\cdot 10^9 C}{(0.2437m-0.7m)^2} =-161.9 V/m
poiting towards the center of piece 6, since the charge is negative.

(e) missing details on this question.
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1. Describe what is happening at point A when these 3 vectors act on point A. 2. Describe what happen to the resultant vector at
zavuch27 [327]

Answer: Don't know sorry

Explanation:

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3 years ago
A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the
Sholpan [36]

Answer:

Change of momentum = M (Vf - (-Vi))   where V represents the scalar speeds of the ball or

I = M (ui + uf)  and I is the impulse ΔM V = I     Force = Change in Momentum

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2 years ago
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