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allsm [11]
3 years ago
9

1. In this experiment, the procedure instructs you to dissolve solid potassium hydrogen tartrate (KHT) in two different solvents

. What are these two solvents? (2 pts)
Chemistry
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

Water

Explanation:

Solid potassium hydrogen tartrates (KHT) is soluble in water. This is especially at room temperature.

The solvent for KHT is water.

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How many moles of tin atoms are in a pure tin cup with a mass of 37.6 g ?
Georgia [21]
Tin is an element called Stannum and has the symbol Sn. Molar mass is the mass of 1 mol of a compound, 1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up an element or molecules making up a compound. 
While the number of atoms making up 1 mol is the same for any element, the weight of 1 mol of substance varies from one another.
In tin(Sn) molar mass - 118.71 g/mol
In 118.71 g - there's 1 mol of tin
therefore in 37.6 g of tin - 1 x 37.6 / 118.71 = 0.31 mol 
In 37.6 g of tin, there's 0.31 mol 
3 0
3 years ago
3. Round 87.073 meters to three significant figures. Write your answer in scientific notation. Step 1: 87.073 rounds to _______
Nat2105 [25]

Answer:

see below

Explanation:

3.  87.073 meters to three significant figures.

  = 87.1 meters

2.  Write the number in scientific notation. _____meters​

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6 0
3 years ago
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In Mendelian genetics, when a tall plant is crossed with a short plant, the offspring will be:
Annette [7]
Some offspring may be tall, some may be short, and some may be medium medium sized.
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3 years ago
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For an aqueous solution of hf, determine the van't hoff factor assuming 0% and 100% ionization, respectively. a solution is made
Snowcat [4.5K]
According to Osmotic pressure equation:

π = i M R T

When π =0.307 atm & M = 0.01 mol & R (constant)= 0.0821 L-atom/mol-K &
T= 22+273 = 295 Kelvin

So Van't half vector i = π / (MRT)
                                   = 0.307 / (0.01 * 0.0821 * 295)
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When there is no dissociation, i = no. of moles of Hf in 1 L of solution = (1-X) 
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HF(aq) + H2O (L) ⇆ H3O (aq) + F (aq)
(1-X)                                X              X

∴ i = (1-X) + (2x)

 1.27 = 1+X
∴X= 1.27 - 1 = 0.27 
∴ the percent ionization of the acid X = 27 %
7 0
2 years ago
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YIkES One thing u can do i ask your teacher about it or say that u need help with it the cant make fun of u because u need help with your work.

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