6 is the answer just did it
<span>One mol of NaCl (6.02 x1023 formulas) has a mass of 58.44 g. Concept 2. The relation between molecular (formula) mass and molar mass. To obtain one mole of copper atoms (6.02 x 1023 atoms), weigh out 63.55 g copper.</span>
Answer:
![r=-k[H_2][O_2]^{1/2}](https://tex.z-dn.net/?f=r%3D-k%5BH_2%5D%5BO_2%5D%5E%7B1%2F2%7D)
Explanation:
Hello!
In this case, according to the chemical reaction:
H2 + 1/2 O2 --> H2O
Since both hydrogen and oxygen are the reactants and the rate laws are written in terms of the concentration of reactants and the rate constant, we obtain:
Whereas the negative sign represents the consumption of those reactants and the power 1/2 the stoichiometric coefficient of oxygen in the reaction.
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Answer:
Mass of Rb-87 is 86.913 amu.
Explanation:
Given data:
Average mass of rubidium = 85.4678 amu
Mass of Rb-85 = 84.9117
Ratio of 85Rb/87Rb in natural rubidium = 2.591
Mass of Rb = ?
Solution:
The ration of both isotope is 2.591 to 1. Which means that for 2.591 atoms of Rb-85 there is one Rb-87.
For 100% naturally occurring Rb = 2.591 + 1 = 3.591
% abundance of Rb-85 = 2.591/ 3.591 = 0.722
% abundance of Rb-87 = 1 - 0.722= 0.278
84.9117 × 0.722 + X × 0.278 = 85.4678
61.306 + X × 0.278 = 85.4678
X × 0.278 = 85.4678 - 61.306
X × 0.278 = 24.1618
X = 24.1618 / 0.278
X = 86.913 amu
