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Mnenie [13.5K]
3 years ago
5

Which statement is true about sodium hydroxide (NaOH)? It is a salt because it increases the concentration of metallic ions. It

is a salt because it is formed by the reaction of an acid and a base. It is a base because it increases the concentration of hydronium ions. It is a base because it increases the concentration of hydroxide ions.
Chemistry
2 answers:
Korolek [52]3 years ago
5 0
Well you see its part sodium and sodium is another word for salt so It is a salt because it is formed by the reaction of an acid and a base
Leya [2.2K]3 years ago
3 0

Your answer is "It is a base because it increases the concentration of hydroxide ions." Because Sodium Hydroxide is 1, a base and 2, a concentration of hydroxide. Hope this helps you out!

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A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab
77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

  • By definition, pH = -log[H_3O^+].
  • NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq).
  • From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: [NaOH] = [OH^-].
  • Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: [OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}.
  • We also know that pOH = 14.00 - pH = -log[NaOH]. Take the antilog of both sides: 10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}.
  • Solve for the mass of NaOH: m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V.

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g

7 0
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