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Readme [11.4K]
3 years ago
5

I forgot how to do this ;;;

Physics
1 answer:
Anit [1.1K]3 years ago
8 0

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (10 m/s − 5 m/s) / 4 s

a = 1.25 m/s²

Work = force × distance

First, find the distance traveled.

v² = v₀² + 2aΔx

(10 m/s)² = (5 m/s)² + 2 (1.25 m/s²) Δx

Δx = 30 m

Now find the work:

W = (600 kg × 1.25 m/s²) (30 m)

W = 22,500 J

Alternative, work = change in energy.

W = ΔKE

W = ½ mv² − ½ mv₀²

W = ½ m (v² − v₀²)

W = ½ (600 kg) ((10 m/s)² − (5 m/s)²)

W = 22,500 J

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\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}

b) Finding total distance :

Distance travelled from 0 s to 5 s :

  • 1/2 x 5 x 30 = 75 m

Distance travelled from 5 s to 10 s :

  • 5 x 30 = 150 m

Distance travelled from 10 s to 15 s :

  • 150 + 1/2 x 5 x 5
  • 150 + 12.5 = 162.5 m

Distance travelled from 15 s to 20 s :

  • 36 x 5 + 1/2 x 5 x 4
  • 180 + 10 = 190 m

Distance travelled from 20 s to 25 s :

  • 45 x 5 + 1/2 x 5 x 5
  • 225 + 12.5 = 237.5 m

Distance travelled from 25 s to 30 s :

  • 40 x 5 + 1/2 x 10 x 5
  • 200 + 25 = 225 m

Distance travelled from 30 s to 35 s :

  • 20 x 5 + 1/2 x 20 x 5
  • 100 + 50 = 150 m

Distance travelled from 35 s to 40 s :

  • 1/2 x 20 x 5
  • 50 m

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

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  • 31 m/s

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