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3 years ago

I forgot how to do this ;;;

Physics

1 answer:

Anit [1.1K]3 years ago

8 0

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (10 m/s − 5 m/s) / 4 s

a = 1.25 m/s²

Work = force × distance

First, find the distance traveled.

v² = v₀² + 2aΔx

(10 m/s)² = (5 m/s)² + 2 (1.25 m/s²) Δx

Δx = 30 m

Now find the work:

W = (600 kg × 1.25 m/s²) (30 m)

W = 22,500 J

Alternative, work = change in energy.

W = ΔKE

W = ½ mv² − ½ mv₀²

W = ½ m (v² − v₀²)

W = ½ (600 kg) ((10 m/s)² − (5 m/s)²)

W = 22,500 J

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TiliK225 [7]

Answer:

No number answer; don't want to pull out a calculator lol

Explanation:

Capacitors are added in parallel; opposite of resistors.

So for 9, add 10 and 2.5 then do ((1/12.5)+(1/.3))^-1.

For 10, add 0.75 and 15 first, then the rest is the same idea as 9.

4 0

3 years ago

A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac

lana66690 [7]

Answer:

charges of the beads is 1.173 × $10^{-15}$ C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know force for mass

force = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 × $10^{9}$ )

so charges of the beads = 1.173 × $10^{-15}$ C

3 0

3 years ago

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of

solong [7]

Answer:

The velocity of the man from the frame of reference of a stationary observer is, V₂ = 5 m/s

Explanation:

Given,

Your velocity, V₁ = 2 m/

The velocity of the person, V₂ =?

The velocity of the person relative to you, V₂₁ = 3 m/s

According to the relative velocity of two

V₂₁ = V₂ -V₁

∴ V₂ = V₂₁ + V₁

On substitution

V₂ = 3 + 2

= 5 m/s

Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s

8 0

3 years ago

A monkey has a bit of a heavy for on the gas pedal. As soon as the light turns green the monkey pushes the gas pedal to the floo

Andrei [34K]

Answer:

$s=6.86m/s^2$

Explanation:

Hello,

In this case, considering that the acceleration is computed as follows:

$a=\frac{v_{final}-v_{initial}}{t}$

Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:

$a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2$

Regards.

3 0

3 years ago

Pls help i will give u brianliest!

Fofino [41]

Answer:

Explanation:

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3 0

3 years ago