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jekas [21]
3 years ago
8

A hi-lo lifts an 25 N skid to top of a pallet rack. The pallet rack is 3.6 meters tall. The hi-lo takes 12 seconds to get the sk

id on top. Calculate the power output of the hi-lo.
Physics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

7.5Watts

Explanation:

Given parameters:

Force of lift  = 25N

Height  = 3.6m

Time  = 12s

Unknown:

Power output  = ?

Solution:

Power is the rate at which work is done ;

     Power  = \frac{force x height }{time}  

   Power  = \frac{25 x 3.6}{12}    = 7.5Watts

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a.Calculate the average speed (in km/h) of Charlie, who runs to the store 4 kilometers away in 30 minutes. b.Calculate the dista
sveta [45]

as per the question charlie runs to the store which is  4 km away

hence the total distance covered [S] is 4 km

he takes 30 minutes to reach the store.

hence the total time taken [t] = 30 minutes=0.5 hour

We have to calculate the average speed.

the average speed[v]= =\frac{S}{t}

                                   =\frac{4 km}{0.5 hour}

                                    =8 km/hour

then we have to calculate the total distance traveled by charlie in 1 hour.

the distance covered S= V_{avg} *t

                                      =8 km/hour ×1 hour

                                      =8 km

Hence the average speed of charlie is 8 km/hour and he covers a distance of 8 km in 1 hour.

7 0
3 years ago
Which of the following chemical equations demonstrates that atoms are conserved during a chemical reaction?
mr_godi [17]

Answer:

2Mg + O2 → 2MgO

Explanation:

this is what your looking for

8 0
3 years ago
A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif
Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

v(t)=-gt-v_e\times \ln \frac{m-rt}{m}

v = velocity of rocket at time t

g = Acceleration due to gravity =9.8 m/s^2

v_e = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})

v(60) = 668.97 m/s

Height of the rocket = h

Velocity=\frac{Displacement}{time}

668.97 m/s=\frac{h}{60 s}

h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km

Height of the rocket be one minute after liftoff is 40.1382 km.

4 0
3 years ago
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.6 vibrations
tangare [24]

Answer:

\lambda = 25.79\ cm

Explanation:

given,

Wave vibrates = 37.6

time = 27.9 s

maximum distance travel = 450 cm

time = 11.3 s

wavelength = ?

frequency of wave

f=\dfrac{37.6}{27.9}

f = 1.35 Hz

Speed of wave

v = \dfrac{450}{11.3}

v = 39.82 cm/s

wavelength of wave

v = fλ

\lambda =\dfrac{v}{f}

\lambda =\dfrac{34.82}{1.35}

\lambda = 25.79\ cm

Hence, wavelength of the wave is equal to 25.79 cm.

8 0
3 years ago
A race car drives one lap around a race track that is 500 meters in length.
pychu [463]

Explanation:

Check out the picture I drew for a minute before reading this...

B. Distance [the red line] is a scalar quantity reflecting how far an object has traveled. Displacement [the green line] is a vector quantity reflecting how far an object has moved from a point. The key difference is that distance can be any sort of path while displacement is always a vector (or a straight line) between a starting point and a finishing point. Sometimes distance and displacement are equal to one another. Sometimes you have a distance traveled, but zero displacement overall; which is what's going on in your question.

A. The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.

3 0
3 years ago
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