What is the volume of 2400kg of gasoline (petrol) if the density of petrol is 0.7g/km3
1 answer:
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Answer:
The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.
Explanation:
Maximum speed is :
v (max) = Aω
Speed v at any displacement y is given by
=
(
-
) ........................................................ i
And,
v = v (max)
or, 2 × v = Aω .................................................... ii
Eliminating ω from equations i and ii,
=
(
-
)
or, = (
)
=(
)
or, y = 3.56 cm.
Answer:
(a) = 4.19 x
N, and its direction is towards
.
(b) It must be placed inside a hollow shell.
Explanation:
Let, = 165 kg,
= 465 kg,
= 60 kg, and the distance between
and
is 0.340 m.
(a) Since is placed midway between
and
, then its distance to both masses is 0.170 m.
From the Newton's law of universal gravitation,
F =
Where all variables have their usual meaning.
Then,
a. =
-
=
= 2.25 x N
=
= 6.44 x N
∴ = = 6.44 x
- 2.25 x
= 4.19 x N
The net force exerted by the two masses on the 60 kg object is 4.19 x N.
(ii) // = /
/ - /
/
= 6.44 x - 2.25 x
= 4.19 x N
(iii) The direction of the net force is to the right i.e towards .
(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.