Answer:
p = 727.273 kg/m3, y = 7134.545 N/m^3, SG = 0.7273
Explanation:
Density is simply the amount of mass of a substance per unit of volume. It can be found by dividing the mass in kg by the volume im m^3:

Specific weight is the weight of the substance per unit of volume. The weight is the mass of the material times the gravity, and it represents the force that the earth exerts on an object. Another way of calculate this value, its multiplying the density of the fuel times the gravity. Then:

Specific Gravity is the ratio of the density of the substance to the density of a reference substance. For liquids, the reference substance is water at 4°C, which has a density of about 1000 kg/m^3.

<u>Answer:</u>
No, Changing subscripts is not the step of balancing a chemical equation
<u>Explanation:</u>
In balancing a chemical equation you have to keep one thing in mind that the no of atoms and elements on both sides such as reactant (before reaction) and product( after a reaction) must be equal. Coefficients are added to equal the no of atoms and elements, but we will not change the subscript.
-- 1 ton is defined as 2,000 pounds.
-- 1 metric ton (or tonne) is defined as 1,000 kilograms of mass.
On Earth,1,000 kilograms of mass weigh 2,204.6 pounds ... 204.6 pounds
more than 1 ton.
On, say, the moon, however, 1,000 kilograms of mass weigh
only 364.9 pounds ... about 18% of 1 ton.
Answer:
d = 1.07 mile
Explanation:
The rationale for this method is that the speed of light is much greater than the speed of sound, the definition of speed in uniform motion is
v = d / t
d = v t
the speed of sound is worth
v = 343 m / s
Therefore, the speed of sound must be multiplied by time to do this, all the units must be in the same system, as the distance in miles is requested
v = 343 m/s (1mile/1609 m) (3600s/1 h) = 343 (2.24) = 767.4 mile/h
v = 343 m / s (1 mile / 1609 m) = 0.213, mile/ s
If the measured time is t = 5s we multiply it by the speed
we substitute
d = 0.213 5
d = 1.07 mile
If you want to calculate the speed, this method in general is not widely used, since you must know the distance where the lightning occurred, which is relatively complicated.