16.7 m/s
<em>To</em><em> </em><em>deter</em><em>mine</em><em> </em><em>the </em><em>speed</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>formula</em><em>:</em><em> </em><em>Dista</em><em>nce</em><em> </em><em>÷</em><em> </em><em>Time</em><em> </em><em>so</em><em>,</em><em> </em><em>5</em><em>0</em><em> </em><em>÷</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>6</em><em>.</em><em>6</em><em>6</em><em>.</em><em>.</em><em>.</em><em> </em><em>(</em><em> </em><em>rounde</em><em>d</em><em> </em><em>off</em><em> </em><em>to</em><em> </em><em>1</em><em>.</em><em>d</em><em>.</em><em>p</em><em> </em><em>is</em><em> </em><em>1</em><em>6</em><em>.</em><em>7</em><em>)</em><em>.</em>
You have to have electrons that are in the materials conduction band. Then you apply a voltage across the material.
Answer:
118800 seconds
Explanation:
Given :
Voltage, V = 1.2 V
Resistance, R = 22 Ω
Applying Ohm's law, we get
Voltage, V = IR
Current 
I = 0.0545 A
Rate = 1800 mAh
Time taken, 
= 33 hr
= 118800 s
On the whole, the metals burn in oxygen to form a simple metal oxide. Beryllium is reluctant to burn unless it is in the form of dust or powder. Beryllium has a very strong (but very thin) layer of beryllium oxide on its surface, and this prevents any new oxygen getting at the underlying beryllium to react with it.
Answer:
b) Cells will pass through the G1/S checkpoint even if conditions are not ideal for cell division.
Explanation:
In the given problem, if there exists a gain-of-function mutation for the given cell, there would not be the formation of cyclin E when there is the possibility of cells movement via the checkpoint of the G1/S, even when there are non-deal conditions for the division of cell. Thus, the correct option in the lists of options is the option b.
