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Sergio [31]
3 years ago
14

A capacitor charging circuit consists of a battery, an uncharged 20 μF capacitor, and a 6.0 kΩ resistor. At t = 0 s the switch i

s closed; 0.15 s later, the current is 0.46 mA . Part A What is the battery's emf?
Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

Battery voltage will be equal to 9.65 volt

Explanation:

We have given capacitance C=20\mu F=20\times 10^{-6}F

Resistance R=6kohm=6000ohm

Time constant of RC circuit is

\tau =RC=20\times 10^{-6}\times 6000=0.12sec

Time is given t = 0.15 sec

Current i = 0.46 mA

Current in RC circuit is given by

i=\frac{V}{R}e^{\frac{-t}{\tau }}

0.00046=\frac{V}{6000}e^{\frac{-0.15}{0.12 }}

0.00046=\frac{V}{6000}\times 0.286

V = 9.65 volt

So battery emf will be equal to 9.65 volt

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Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro
Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0
3 years ago
This is a net gain or loss of electrons. *
krok68 [10]
A net gain of electrons.
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3 years ago
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The u.s has sent unmanned spacecrafts to ___ the planets in our solar system
kirill115 [55]
I think it's C. if we're talking about a rover.

But if it's a rocket that's computerized and automatic (synonym of unmanned)... Then it's B.
6 0
3 years ago
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A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?
Finger [1]

Answer:

196J

Explanation:

Given parameters:

Mass of skateboard  = 1kg

Height off the ground  = 20m

Unknown:

Potential energy  = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

      Potential energy  = mass x acceleration due gravity x height

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The type of energy that depends on position is called
Maurinko [17]

Answer:

a. potential energy

Explanation:

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3 years ago
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