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Sergio [31]
3 years ago
14

A capacitor charging circuit consists of a battery, an uncharged 20 μF capacitor, and a 6.0 kΩ resistor. At t = 0 s the switch i

s closed; 0.15 s later, the current is 0.46 mA . Part A What is the battery's emf?
Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

Battery voltage will be equal to 9.65 volt

Explanation:

We have given capacitance C=20\mu F=20\times 10^{-6}F

Resistance R=6kohm=6000ohm

Time constant of RC circuit is

\tau =RC=20\times 10^{-6}\times 6000=0.12sec

Time is given t = 0.15 sec

Current i = 0.46 mA

Current in RC circuit is given by

i=\frac{V}{R}e^{\frac{-t}{\tau }}

0.00046=\frac{V}{6000}e^{\frac{-0.15}{0.12 }}

0.00046=\frac{V}{6000}\times 0.286

V = 9.65 volt

So battery emf will be equal to 9.65 volt

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