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3 years ago

What happens to the water particles in a wave?

2 answers:

8 0

Answer: waves transport energy, not water. As a wave crest passes, the water particles move in circular paths. The movement of the floating inner tube is simulacra to the movement of the water particles. Water particles rise as a wave crest approaches.

Explanation:

bagirrra123 [75]3 years ago

7 0

Answer:

the answer is A.) The water particles move in a circular pattern.

Explanation:

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Static electricity is the

guapka [62]

Unlike charges attracting each other

4 0

3 years ago

Read 2 more answers

A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms

Aleonysh [2.5K]

Explanation:

It is given that,

Power of EM waves, P = 1800 W

We need to find the intensity at a distance of 5 m. Also, the rms value of the electric field.

Intensity,

$I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{1800}{4\pi\times (5)^2}\\\\I=5.72\ W/m^2$

The formula that is used to find the rms value of the electric field is as follows :

$I=\epsilon_o cE^2_{rms}$

c is speed of light and $\epsilon_o$ is permittivity of free space

So,

$E_{rms}=\sqrt{\dfrac{I}{\epsilon_o c}}\\\\E_{rms}=\sqrt{\dfrac{5.72}{8.85\times 10^{-12}\times 3\times 10^8}}\\\\E_{rms}=46.41\ V/m$

Hence, this is the required solution.

4 0

3 years ago

A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 1.00 m/s when it starts to rain with i

Vera_Pavlovna [14]

Answer:

Explanation:

1. We use the conservation of momentum for before the raining and after. And also we take into account that in 0.5h the accumulated water is

100kg/h*0.5h = 50kg

$p_{b}=p_{a}\\M_{b}v_{b}=(M_{b}+m_{r})v_{a}\\v_{a}=\frac{M_{b}v_{b}}{M_{b}+m_{r}}=\frac{250kg*1\frac{m}{s}}{250kg+50kg}=0.83\frac{m}{s}$

2. the momentum does not conserve because the drag force of water makes that the boat loses velocity

3. If we assume that the force of the boat before the raining is

$F=ma=m\frac{v-v_{0}}{t-t_{0}}=250kg\frac{1m}{s^{2}}=250N$

where we have assumed that the acceleration of the boat is 1m/s{2} just before the rain starts

And if we take the net force as

$F_{net}=M_{b}a_{net}=F-F_{d}=250N-bv^{2}\\F_{net}=250N-0.5N\frac{s^{2}}{m^{2}}(1\frac{m}{s})^{2}=249.5N\\a_{net}=\frac{249.5N}{M_{b}}=\frac{249.5N}{250kg}=0.99\frac{m}{s^{2}}$

where we take v=1m/s because we are taking into account tha velocity just after the rain stars.

I hope this is useful for you

regards

5 0

3 years ago

At the end of the movie Titanic, Rose lies on a piece of furniture, floating in the ocean, and Jack drowns. A common objection p

julsineya [31]

Answer:

If jack is in the piece of furniture it would submerge.

Explanation:

The piece of furniture would submerge if the weight applied on the furniture is greater than the maximum buoancy force the water can provide.

maximum buoacy force = density of liquid × volume submerged× acceleration due to gravity.

= $1025\times v\times 9.8$

v = area × thickness of pine

$1.5\times 5\times 10^{-2}$

= 0.075 $m^{3}$

therefore buoancy force = 1025×0.075×9.8 N

= 753.375 N

weight of rose alone = 46×9.8 N = 450.8 N

weight of jack alone = 58×9.8 = 568.4 N

weight of pine = density of pine × volume of pine

= 350 × 0.075= 26.25 N

weight of pine + weight of rose = 450.8+26.25=477.05 N

weight of pine + rose + jack = 477.05 + 568.4 = 1045.45 N

therefore if jack is in the piece of furniture it would submerge.

4 0

3 years ago

Before using a string in a comparison, you can use either the To Upper method or the To Lower method to convert the string to up

diamong [38]

Answer:

True, check attachment for code

Explanation:

To convert java strings of text to upper or lower case, we can use and inbuilt methods To Uppercase and To lower case.

The first two lines of code will set up a String variable to hold the text "text to change", and then we print it out.

The third line sets of a second String variable called result.

The fourth line is where the conversion is done.

We can compare the string

We can compare one string to another. (When comparing, Java will use the hexadecimal values rather than the letters themselves.) For example, if we wanted to compare the word "Fat" with the word "App" to see which should come first, you can use an inbuilt string method called compareTo.

Check attachment for the code

3 0

3 years ago