26.4 kg of calcium hydroxide (Ca(OH)₂)
Explanation:
We have the following chemical reaction:
CaO + H₂O → Ca(OH)₂
molecular weight of Ca(OH)₂ = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms + atomic mass of H × number of H atoms
molecular weight of Ca(OH)₂ = 40 × 1 + 16 × 2 + 1 × 2 = 74 g/mole
molecular weight of CaO = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms
molecular weight of CaO = 40 + 16 = 56 g/mole
number of moles = mass / molecular weight
number of moles of CaO = 20 / 56 = 0.357 kmoles
Taking in account the chemical reaction we devise the following reasoning:
if 1 kmole of CaO produces 1 kmole of Ca(OH)₂
then 0.357 kmoles of CaO produces X kmoles of Ca(OH)₂
X = (0.357 × 1) / 1 = 0.357 kmoles of Ca(OH)₂
mass = number of moles × molecular weight
mass of Ca(OH)₂ = 0.357 × 74 = 26.4 kg
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number of moles
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Answer:
magnesium metal
Explanation:
According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:
From ∆G°= -nFE°cell
E°cell= -∆G°/nF= -(-411×10^3/96500×6)
E°cell= 0.7098V
But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.
E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode
Hence
E°anode=E°cathode - E°cell
E°anode= -1.66-0.7098= -2.37V
This is the reduction potential of Mg hence the anode material was magnesium metal
Answer:
B.) The molecule is a branched hydrocarbon.
Explanation:
A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.
Answer:
This is True
Explanation:
A fossil is any remains or trace of an ancient organism. Fossils include body fossils, left behind when the soft parts have decayed away, as well as trace fossils
