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sladkih [1.3K]
3 years ago
11

The rate of effusion of oxygen to an unknown gas is 0.935. what is the other gas?

Chemistry
1 answer:
Kamila [148]3 years ago
4 0

Answer:

N2

Explanation:

Rate of effusion is defined by Graham's Law:  

(Rate 1/Rate 2) = (sqrt (M2)/ sqrt (M1))

(Where M is the molar mass of each substance. )

Molar Mass of oxygen, O2, is 32 (M1).

Rate of effusion of O2 to an unknown gas is .935(Rate 1).  

Rate 2 is unknown so put 1.

Solve for x (M2).

.935/1 = sqrt x/ sqrt32

.935 x sqrt 32 = sqrt x

5.29 = sq rt x

5.29^2 = 27.975 = 28  

N2 has a molar mass of 28 so it is the correct gas.

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Q3. A student added water to calcium oxide to make calcium hydroxide
galina1969 [7]

26.4 kg of calcium hydroxide (Ca(OH)₂)

Explanation:

We have the following chemical reaction:

CaO + H₂O → Ca(OH)₂

molecular weight of Ca(OH)₂ = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms + atomic mass of H × number of H atoms

molecular weight of Ca(OH)₂ = 40 × 1 + 16 × 2 + 1 × 2 = 74 g/mole

molecular weight of CaO = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms

molecular weight of CaO = 40 + 16 = 56 g/mole

number of moles = mass / molecular weight

number of moles of CaO = 20 / 56 = 0.357 kmoles

Taking in account the chemical reaction we devise the following reasoning:

if        1 kmole of CaO produces 1 kmole of Ca(OH)₂

then   0.357  kmoles of CaO produces X kmoles of Ca(OH)₂

X = (0.357 × 1) / 1 = 0.357 kmoles of Ca(OH)₂

mass = number of moles × molecular weight

mass of Ca(OH)₂ = 0.357 × 74 = 26.4 kg

Learn more about:

number of moles

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6 0
2 years ago
A standard galvanic cell is constructed so that the overall cell reaction is as given below where M is an unknown metal. 2 Al3+(
jasenka [17]

Answer:

magnesium metal

Explanation:

According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:

From ∆G°= -nFE°cell

E°cell= -∆G°/nF= -(-411×10^3/96500×6)

E°cell= 0.7098V

But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.

E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode

Hence

E°anode=E°cathode - E°cell

E°anode= -1.66-0.7098= -2.37V

This is the reduction potential of Mg hence the anode material was magnesium metal

5 0
3 years ago
What is indicated by the methyl-prefix?
lozanna [386]

Answer:

B.) The molecule is a branched hydrocarbon.

Explanation:

A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.

6 0
1 year ago
Fossils are the preserved remains or traces of an organism that used to be alive.
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Answer:

This is True

Explanation:

A fossil is any remains or trace of an ancient organism. Fossils include body fossils, left behind when the soft parts have decayed away, as well as trace fossils

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Answer:genes

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