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Elis [28]
3 years ago
12

calculate the amount of time required to rise the temperature of 0.50 liter of water from 0.0 c to 10.0 c if the energy is suppl

ied at rate of 1100 joules per second
Chemistry
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

The amount of time required to rise the temperature of 0.50 liter of water from 0.0 c to 10.0 c is 19 seconds

Explanation:

1100 J/s is the energy supplied so, we have to set, the energy to that ΔT, which is 10°C (10°-0°)

Q = m . C. ΔT

Q =  500g . 4,186J/g°C . 10°C

Remember the water density is 1g/mL, so if we have 0,5 L, we should get the convertion to g. (1ml = 1x10*-3 L)

1x10*-3 L ____ 1 g

0,5 L _____ (0,5 L . 1 g)/ 1x10*-3 L = 500g

4,186J/g°C, this value is known as specific heat of water. It is a known value.

Q =  500g . 4,186J/g°C . 10°C = 20930 J

Now the final rule of three:

1100 J supplies at _____ 1 second

20930 J supplies at _____ (20930 J . 1 s) / 1100 J =19,02 s

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kow [346]

Answer:

The theoretical yield of Cu(s) in moles is 60.15 moles

Explanation:

Step 1: Data given

Number of moles CuO = 70.8 moles

Number of moles NH3 = 40.1 moles

Molar mass CuO = 79.545 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles

There will remain 70.8 - 60.15 = 10.65 moles CuO

Step 3: Calculate moles Cu

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

For 40.1 moles NH3 we'll have 60.15 moles Cu

The theoretical yield of Cu(s) in moles is 60.15 moles

8 0
4 years ago
Answer ASAP Please this is a timed test
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