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tigry1 [53]
3 years ago
6

Balance the following equations:

Chemistry
1 answer:
neonofarm [45]3 years ago
7 0
Hope this helps! If you dont understand balancing equations in general, say so in the comments, I’m happy to help

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Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
4 years ago
A solution has a volume of 500 ml and contains 0.570 mol of nacl what is the molarity
vichka [17]

Answer: 1.14 M

Explanation:

500 mL is equal to 0.5 L.

So, the molarity is (0.570)/(0.5) = 1.14 M

7 0
2 years ago
What is the density of platinum
Alex Ar [27]

Answer:

21.45 g/cm3

Explanation:

6 0
3 years ago
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What are substances that have the same composition, but different structures, known as?
dimulka [17.4K]
The answer is Allotropes.
8 0
4 years ago
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A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many
ladessa [460]
The amount of HCl required for one experiment - 13.5 µl 
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L 
since one experiment uses up - 13.5 x 10⁻⁶ L 
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L  = 1.8 x 10⁴ times 
the experiment can be carried out 18000 times 
6 0
3 years ago
Read 2 more answers
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