Most plastics have refractive indices in the range from 1.3 to 1.7, but some high-refractive-index polymers can have values as high as 1.76. For infrared light refractive indices can be considerably higher. Germanium is transparent in the wavelength region from 2 to 14 µm and has a refractive index of about 4.
Explanation:
First, simplify the circuit. Then calculate the parallel and consecutive resistances to find the answer.
Answer:
blue
You see white. What happens when you shine cyan light on a magenta shirt? You see blue.
Explanation:
Answer:
a) 0.0036 J & 0.0135 J
b) 0.0099 J
Explanation:
Given that
Capacitance of a capacitor, C(i) = 12.5*10^-6 F
Potential difference across the capacitor, V = 24 V
Dielectric constant, k = 3.75
Energy in a capacitor is given by the formula
U = ½ CV²
Now, applying this to our solution, we have.
a, the energy stored before the dielectric was inserted is 0.0036. After inserting the dielectric, we then take cognizance into it, essentially multiplying by the constant of the dielectric, we got 0.0135 J
b) Now, Change in energy is gotten by subtracting the two energies, and we have
ΔU = U - U(1)
ΔU = 0.0036 - 0.0135
ΔU = 00099 J
See attachment for calculation
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