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3 years ago

Which is a TRUE statement about salt water?

2 answers:

6 0

I think the best answer from the given choices is option D. <span>Salt water is made up of more than one pure substance. It consists of salt and water. When each component exist alone in a container they are considered as pure substance however when mixed they are now a solution.</span>

Phantasy [73]3 years ago

3 0

Answer:

the answer is D

Explanation:

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What is combination reaction and also define it's properties?

tigry1 [53]

Answer:

This is when two or more compounds or elements react to form a single product.

In these reactions new substances are produced or synthesized.

in simple terms the elements or compounds are converted to something new.

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3 years ago

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_____ NaPO4+_____KOH

Artist 52 [7]

NaPO4 + KOH -> KPO4 + NaOH
already balance

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3 years ago

A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the

Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

$V_2 = \frac{P_1P_2}{P_2}$ that is V₂ = $\frac{1atm*1.32L}{90atm}$ = $\frac{11}{750}L$ or 0.01467L

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3 years ago

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An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The

GuDViN [60]

Answer:Mass of Potassium chloride =1.762g

Explanation:

Mass of empty beaker = 23.100 g

Mass of beaker with Potassium chloride = 24.862g

Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride - Mass of empty beaker = 24.862-23.100 = 1.762g

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3 years ago

Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo

Romashka-Z-Leto [24]

Answer:

$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

Explanation:

Volume of a cone:

$\displaystyle V=\frac{1}{3} \pi r^2 h$

We have $\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}$ and we want to find $\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?$ when the height is 2 cm.