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kondaur [170]
4 years ago
11

What is the formula related to volume

Physics
1 answer:
Dovator [93]4 years ago
4 0
Volume=length x breadth x height. It unit is M3
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Describe 2 applications of surface tension
Andrews [41]
Application of surface tension:
1) A needle placed on water can be made to float due to the surface tension of water.
2) Mosquito eggs can float on water because of its surface tension.
3) Toothpaste contains soap, which reduce the surface tension and helps it spread freely in the mouth.
8 0
3 years ago
A Decay Chain
Strike441 [17]

Answer : The energy released in first step of thorium-232 decay chain is 7.974\times 10^{-13}J

Explanation :

First we have to calculate the mass defect (\Delta m).

The balanced reaction is,

^{232}Th\rightarrow ^{228}Ra+^{4}He

Mass defect = Sum of mass of product - sum of mass of reactants

\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})

\Delta m=(228.0301069+4.002602)-(232.038054)=5.34\times 10^{-3}amu=8.86\times 10^{-30}kg

conversion used : (1amu=1.66\times 10^{-27}kg)

Now we have to calculate the energy released.

Energy=\Delta m\times (c)^2

Energy=(8.86\times 10^{-30}kg)\times (3\times 10^8m/s)^2

Energy=7.974\times 10^{-13}J

The energy released is 7.974\times 10^{-13}J

Therefore, the energy released in first step of thorium-232 decay chain is 7.974\times 10^{-13}J

7 0
3 years ago
6. Convert -180° to radians
icang [17]

Answer:

-3.141593

Explanation:

3 0
4 years ago
Read 2 more answers
A dog is trained to sit and shake hands these traits are most likely
antiseptic1488 [7]
Taught  not inherited

4 0
3 years ago
An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and
Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0
4 years ago
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