Answer:
0.214 L
Explanation:
Step 1: Write the balanced equation
This is a single displacement reaction.
Zn(s) + 2 HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)
Step 2: Calculate the moles corresponding to 0.625 g of Zn
The molar mass of Zn is 65.38 g/mol.
0.625 g × 1 mol/65.38 g = 9.56 × 10⁻³ mol
Step 3: Calculate the moles of H₂ produced from 9.56 × 10⁻³ moles of Zn
The molar ratio of Zn to H₂ is 1:1. The moles of H₂ produced are 1/1 × 9.56 × 10⁻³ mol = 9.56 × 10⁻³ mol.
Step 4: Calculate the volume occupied by 9.56 × 10⁻³ moles of hydrogen
Assuming standard pressure and temperature, 1 mole of hydrogen occupies 22.4 L.
9.56 × 10⁻³ mol × 22.4 L/1 mol = 0.214 L
Answer:
Possibly
Explanation:
Cold water does not boil faster than hot water. ... As a result, cold water will be absorbing heat faster while it is still cold; once it gets up to the temperature of hot water, the heating rate slows down and from there it takes just as long to bring it to a boil as the water that was hot to begin with.
Answer: Option (c) is the correct answer.
Explanation:
As we know that density the amount of mass present in per unit volume.
Mathematically, Density = 
So, it means that density is inversely proportional to volume. Hence, when there will be decrease in density of a substance then there will be increase in its volume. That is, expansion of substance will take place.
Also, boiling point of copper is 2,562 degree celsius but we are heating it up to a temperature of 95 degree celsius. This means that copper will remain in liquid state at this temperature.
Thus, we can conclude that a change which occurs in a sample of copper is that copper sample will expand.
Answer:
79.0 g
Explanation:
1. Gather the information in one place.
MM: 148.89 253.81
2NaI + Cl2 → I2 + 2NaCl
m/g: 67.3
2. Moles of I2
n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2
2. Moles of NaI needed
From the balanced equation, the molar ratio is 2 mol NaI: 1 mol I2
n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI
3. Mass of NaI
m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI
It takes 79.0 g of NaI to produce 67.3 g of I2.
Answer:
Ag2S
Explanation:
10.8 gm of silver, 12.4 gm of silver sulfide, so 12.4 -10.8 = 1,6 gm of sulfur
silver atomic weight is 108, sulfur atomic weight is 32 so
10.8/108; = 0.10 mole Ag 1.6/32 = 0.05 mole sulfur
so there is a 2:1 ratio of silver to sulfur, so the compound is 2 silver 1 sulfur or Ag2S
