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s344n2d4d5 [400]
3 years ago
10

When 10.8 g of Silver was reacted with Sulfur, 12.4 grams of product was produced (there was only one product). What is the empi

rical formula of the product?
Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

Ag2S

Explanation:

10.8 gm of silver, 12.4 gm of silver sulfide, so 12.4 -10.8 = 1,6 gm of sulfur

silver atomic weight is 108, sulfur atomic weight is 32  so

10.8/108;   = 0.10 mole Ag  1.6/32 = 0.05 mole sulfur

so there is a 2:1 ratio of silver to sulfur, so the compound is 2 silver 1 sulfur or Ag2S

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Draw fischer projection for d-2-ketotetrose
koban [17]
<span>Fischer projection for D-2-ketotetrose is in Word document below.
</span>D-2-ketotetrose is monosaccharide, having both a ketone (a ketose) and four carbons (a tetrose). There are two ketotetroses (the enantiomers) L and D-erythrulose, this is D-erytrhrulose (1,3,4-trihydroxy-2-butanone).
The <span>Fischer projection is </span>two-dimensional<span> representation of a </span>three dimensional organic molecule.

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3 0
4 years ago
What is the mass percent of oxygen in Nickel (III) sulfate?
NeX [460]

The mass percent of oxygen in Nickel(III)sulfate is 23.68 percent.

At first, we look up the atomic masses for the element from the periodic table.

The atomic masses are found to be:

  • Ni is 58.7
  • S is 32
  • O is 16

Next, we determine how many grams of each element are present in one mole of Ni_{2}(SO_{4})_{3}

  • 117.4g(2   mol*58.7) of Ni
  • 96g(3 mol*32) of S
  • 192g(12 mol * 16.00) of O

The mass of one mole  Ni_{2}(SO_{4})_{3} is:

117.4g+96g+192g=405.4g

So, The mass percent of oxygen =(96g/405.4)*100=0.2368*100%\\

                                                    =23.68 % percent.

To learn more about Mass percent, refer to:

  • brainly.com/question/25255030

3 0
2 years ago
What is the answer for this!! plz it due today 5/6/20!!!
Furkat [3]

Answer:)

1. d

2.c

3.c

4.b

Explanation:

Because im smart

7 0
4 years ago
Calculate the mass percent composition of nitrogen in co(nh2)2.
Mashcka [7]
The  mass  percentage  composition  of  nitrogen  in  CO(NH2)2  is 46 .7%

    calculation

%  mass  =   molar  mass  of nitrogen/ molar mass  of  Co(NH2)2 

molar mass  of nitrogen =  14 x2 = 28g/mol  since there is  two  nitrogen atom  in  Co(NH2)2\

molar mass  of CO(NH2)2  = 12 + 16 + (14 x2) +( 2 x2)=  60 g/mol

the %  mass  is therefore =28 /  60  x100   =46.7%
3 0
3 years ago
Read 2 more answers
To titrate 50.00 milliliters of an unknown HC2H3O2 sample, use 43.00 milliliters of a standard 0.1000 M NaOH titrant. What is th
rewona [7]
The molarity of the acid is 0.086 00 mol/L.

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

Since 1 mol of acid reacts with 1 mol of base, we can use the formula

M₁V₁ = M₂V₂

M₁ = ?; V₁ = 50.00 mL
M₂ = 0.1000 mol/L; V₂ = 43.00 mL

M₁ = M₂ × \frac{ V_{2}}{ V_{1}} = 0.1000 mol/L × \frac{43.00 mL}{50.00 mL} = 0.086 00 mol/L
7 0
4 years ago
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