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s344n2d4d5 [400]
3 years ago
10

When 10.8 g of Silver was reacted with Sulfur, 12.4 grams of product was produced (there was only one product). What is the empi

rical formula of the product?
Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

Ag2S

Explanation:

10.8 gm of silver, 12.4 gm of silver sulfide, so 12.4 -10.8 = 1,6 gm of sulfur

silver atomic weight is 108, sulfur atomic weight is 32  so

10.8/108;   = 0.10 mole Ag  1.6/32 = 0.05 mole sulfur

so there is a 2:1 ratio of silver to sulfur, so the compound is 2 silver 1 sulfur or Ag2S

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3h2so4 2b(oh)3 - b2(so4)3 6h2o what is the mole ratio between water and sulfuric acid?
Nutka1998 [239]

Since there is an equal number of each element in the reactants and products of 3H2SO4 + 2B(OH)3 = B2(SO4)3 + 6H2O, the equation is balanced.

<h3>What is Sulfuric acid?</h3>
  • Sulfuric acid (H2S04) is a corrosive substance, that destroys the skin, eyes, teeth, and lungs. Severe vulnerability can result in death. Workers may be harmed from disclosure to sulfuric acid. The level of exposure depends on
  • The sulfuric acid bleaching can substitute the presently assumed oxygen and chlorine stages if the additives are allowed. This bleaching process was also practical for oxygen-bleached hardwood kraft pulp, but it was less compelling for softwood kraft pulp and oxygen-bleached softwood kraft pulp.
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To learn more about Sulfuric acid, refer to:

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8 0
1 year ago
Coal and Diamond are two different form of carbon. which is denser?​
GalinKa [24]

Answer:

diamond is denser because it is more tightly packed than coal

7 0
3 years ago
Read 2 more answers
How far he drove, in miles?
MrRa [10]
The answer is C (xy)
4 0
3 years ago
29.0 argon combine completely with 4.30 g of Sulfur.
Iteru [2.4K]

Answer:

33.3

Explanation:

if we were to add 29.0 of argon and 4.30 of sulfur and that would come out 33.3.

8 0
3 years ago
how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?
defon

Answer:

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

Explanation:

Reaction equation:

(NH4)_{2}CO_{3} → 2NH_{3} + CO_{2} + H_{2} O

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of (NH4)_{2}CO_{3} - 96.09 g

0.148 mol of (NH4)_{2}CO_{3} --  ?? g

=0.148 × 96.09

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

5 0
3 years ago
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