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Nikitich [7]
3 years ago
7

BaO2(s) + 2HCl(aq) → H2O2(aq) + BaCl2(aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated wi

th 25.0 mL hydrochloric acid solution containing 0.0272 g HCl per mL? 0.301 g H2O2 What mass of which reagent is left unreacted?
Chemistry
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

mass H2O2 = 0.31g H2O2

mass unreacted = 0.0745g BaO2

Explanation:

Mw BaO2 = 169.33 g / mol

Mw HCl = 36.46 g/mol

Mw H2O2 = 34.0147 g/mol

LR:

⇒ mol BaO2 = 1.50g BaO2 * mol / 169.33 g = 8.86E-3 mol BaO2 / 1 = 8.86E-3 mol BaO2

⇒ mol HCl = 25.0 mL * 0.0272g / mL * mol / 36.46g = 0.0186 mol HCl / 2 = 9.3E-3 mol HCl.....L.R

mol H2O2:

⇒ 0.0186mol HCl * (mol H2O2 / 2mol HCl) = 9.325E-3 mol H2O2

⇒ g H2O2 = 9.325E-3mol H2O2 * 34.0147g H2O2 / mol H2O2 = 0.31g H2O2

mass of wich reagent is left unreacted:

mol that react BaO2 = 0.0186mol HCl * (mol BaO2 / 2mol HCl) = 9.3E-3mol BaO2

mol that unreacted BaO2 = 9.3E-3 - 8.86E-3 = 4.4E-4 mol BaO2

g unreacted BaO2 = 4.4E-4mol BaO2 * (169.33g BaO2 / mol BaO2) = 0.0745g BaO2

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A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
Circulacion de electrones en un material conductor en determinado tiempo.
barxatty [35]

Answer:

falso

Explanation:

tiempo no determinado El circulation de elctrones

4 0
1 year ago
Do all colors of light have the same energy?
icang [17]
No, darker colors like purple and blue have higher wave frequency which transmit more energy.
6 0
3 years ago
Determine the percentage composition (by mass) of oxygen in NH4NO3.
Brrunno [24]

Answer:

60%

Explanation:

M(NH4NO3) = 2*14 +4*1 +3*16 = 80 g/mol

M(3O) = 3*16 = 48 g/mol

(48/80) *100 % =60% oxygen by mass.

6 0
3 years ago
The digit that would have to be estimated in reading this instrument would be the nearest:
wariber [46]

Answer:

The least count of vernier calipers is 0.01 g.

(B) is correct option.

Explanation:

Given that,

The digit that would have to be estimated in reading this instrument,

According to figure,

We need to calculate the pitch

Using formula of pitch

pitch=\dfrac{distance\ moved}{Number\ of\ complete\ rotation}

Put the value into the formula

pitch=\dfrac{1}{10}

pitch=0.1\ g

We need to calculate the least count of vernier calipers

Using formula of least count

Least\ count=\dfrac{pitch}{number\ of\ vernier\ scale\ division}

Put the value into the formula

Least\ count=\dfrac{0.1}{10}

Least count = 0.01\ g

Hence, The least count of vernier calipers is 0.01 g.

(B) is correct option.

4 0
3 years ago
Read 2 more answers
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