Which statement best represents a hypothesis?

What is the most important simlarity between rusting and burning?

KengaRu [80]

Both are oxidation reactions. Burning is just a lot faster than rusting.

8 0

3 years ago

What is a joule?

Roman55 [17]

A joule is defined as the amount of energy transferred to an object when a force of one newton acts on the object in the direction of its motion through a distance of one meter (1 newton meter or Nm)

3 0

3 years ago

Read 2 more answers

Which substance loses electrons in a chemical reaction? the one that is oxidized, which is the oxidizing agent the one that is r

victus00 [196]

Answer:

The one that is oxidized or the reducing agent

Explanation:

Oxidation results in loss of electrons or an increase in oxidation state.

Reduction results in gain of electrons or decrease in oxidation state.

The element that undergoes oxidation is said to oxidised, similarly the element that undergoes reduction is said to be reduced.

In a redox reaction, both oxidation and reduction takes place.

If a substrate undergoes oxidation or is oxidised, it is also responsible for reduction of the other species, as the total number of electrons should always be conserved.

The substance that undergoes oxidation, releases some electrons, these electrons are taken by the other substrate and it undergoes reduction.

Hence the substance that undergoes oxidation is called the reducing agent, as it is responsible for reduction of other substrate, when oxidizing itself.

Similar thought works for a substance that undergoes reduction or is reduced, works as an oxidizing agent.

7 0

3 years ago

Read 2 more answers

A 1.8 g sample of octane C8H18 was burned in a bomb calorimeter and the temperature of 100 g of water increased from 21.36 C to

melomori [17]

Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

So, heat of combustion of octane per gram is 1723.08 J

Heat of combustion per mole:

1.8 g of octane produces 3101.56 J of heat

1 mole of octane will produce X J of heat

1 mole of octane = 114 g/ mol of octane

So we have:

1.8 g of octane = 3101.56 J

114 g of octane = (3101.56 * 114 / 1.8) J of heat

= 196 432.13 J

= 196. 4 kJ of heat

The heat of combustion of octane per mole is 196.4 kJ /mol.

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

8 0

2 years ago

On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i

ddd [48]

Answer:

1.6 L

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (12 + 273.15) K = 285.15 K

T₂ = (32 + 273.15) K = 305.15 K

Using above equation as:

$\frac{1.5}{285.15}=\frac{V_2}{305.15}$

$V_2=\frac{1.5\cdot \:305.15}{285.15}$

New volume = 1.6 L

8 0

3 years ago

Which statement best represents a hypothesis￼?

Which statement best represents a hypothesis?