Answer:
125.681 torr
Explanation:
The formula to calculate the partial pressure of oxygen:
P(O2) = Pcommon - PCO2 - PN2
1 atm = 760 torr
Therefore you need to find the partial pressure of oxygen:
P(O2) = 760 torr -0.285 torr - 634.034 torr =130.013 torr
- Hope that helped!
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Answer: acetic acid structure
Explanation:
In the lewis structure we have 24 valence electrons
Answer:
6.1×10^8
Explanation:
The reaction is;
Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)
E°cell = E°cathode - E°anode
E°cathode= -0.14 V
E°anode= -0.40 V
E°cell = -0.14-(-0.40)
E°cell= -0.14+0.40
E°cell= 0.26 V
But
E°cell= 0.0592/n log K
E°cell= 0.0592/2 log K
0.26= 0.0296log K
log K = 0.26/0.0296
log K= 8.7838
K= Antilog (8.7838)
K= 6.1×10^8
