Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Given:
One time payment, <em>p </em>= $300
Payment per month, <em>q = </em>$65
Number of months paid, <em>n</em> = 5
The objectiv is to find the amount she paid in 5 months.
Let <em>x </em>be the amount she paid in 5 months. Then the the formula is,
Let's substitute the values.
Hence, total amount paid in 5 months is $625.
<span>50x - 32x^3
= 2x (25 - 16x^2)
hope that helps</span>
Answer:
The required polynomial is .
Step-by-step explanation:
If a polynomial has degree n and are zeroes of the polynomial, then the polynomial is defined as
It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.
According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.
Since 3-3i is zero, therefore 3+3i is also a zero.
Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is
Therefore the required polynomial is .