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3 years ago

12

When Peter first arrives at the Stone Table, what is he surprised to see beyond the Stone Table?

2 answers:

MrRa [10]3 years ago

7 0

NARNIA... He is surprised to see, nothing because he never visited the stone table, I've watched the movies a thousand times and the books and it says nothing about him seeing the stone table.

wel3 years ago

4 0

None this is a trick question. Peter never visited the stone table.

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Lera25 [3.4K]

Answer:

$\frac{1}{4} \div 5 \\ = \frac{1}{20}$

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2 years ago

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jeyben [28]

Answer:

81(x + 2y)(x - 2y)

Step-by-step explanation:

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2 years ago

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antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

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As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

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2 years ago

If f(x) = 5x − 1 and g(x) = 2x2 + 1, what is the value of (f × g)(-3)?

Softa [21]

f(x) = 5x − 1 and g(x) = 2x^2 + 1

(f × g)(x) = (5x − 1)(2x^2 + 1)

(f × g)(x) = 10x^3 - 2x^2 + 5x - 1

Substitute x = - 3

(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1

(f × g)(-3) = 10(-27) - 2(9) -15 - 1

(f × g)(-3) =-270 - 18 - 16

(f × g)(-3) = -236

Answer

- 236

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3 years ago