Question

The current drawn by fluorescent lighting has a high total harmonic distortion. For this case, THD is calculated to be 88%. The true power factor is measured to be 0.72 lagging. What is the displacement power factor (ie. if all harmonics could be filtered out)? Assume the source voltage waveform is undistorted.

Answer 1

Answer:

displacement power factor is 0.959087

Explanation:

given data

THD = 88%

true power factor = 0.72

solution

we get here total harmonic distribution THD is express as here

THD = $\sqrt{\frac{1}{g^2}-1}$       ..............1

her g is distortion factor

so put here value and we will get g that is

0.88² =   $\frac{1}{g^2} -1$    

solve it we get

g = 0.750714

and

displacement power factor is express as

DPF = $\frac{PF}{g}$   .................2  

put here value and we will get

DPF = $\frac{0.72}{0.750714}$    

DPF  = 0.959087