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Degger [83]
3 years ago
6

Why does a foil airplane fly farther than a paper one?

Engineering
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

the reason paper airplanes fly is because of lift the foil has no lift

Explanation:

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Three capillary tubes with different radius (r1=1.0mm, r2=0.1mm, r3=0.01mm) are inserted into the same cup of water. The surface
kobusy [5.1K]

Answer:

you fgykyiihohuoououu

Explanation:

jjj

4 0
3 years ago
For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration will raise the carbon concentratio
diamong [38]

This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

x^2 / Dt = constant

where D is constant

then

x^2 / t = constant

x^2_1 / t₁ = x^2_2 / t₂

x^2_1 t₂ = t₁x^2_2

t₂ = t₁x^2_2 / x^2_1

t₂ = (x^2_2 / x^2_1)t₁

t₂ = ( x_2 / x_1 )^2 × t₁

so we substitute

t₂ = ( 0.0049  / 0.0018  )^2 × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

8 0
2 years ago
An inventor claims to have invented a heat engine that operates between the temperatures of 627°C and 27°C with a thermal effici
Oksana_A [137]

Answer Explanation:

the efficiency of the the engine is given by=1-\frac{T_2}{T_1}

where T₂= lower temperature

           T₁= Higher temperature

we have given efficiency =70%

lower temperature T₂=27°C=273+27=300K

higher temperature T₁=627°C=273+627=900K

efficiency=1-\frac{T_2}{T_1}

                =1-\frac{300}{900}

                 =1-0.3333

                 =0.6666

                 =66%

66% is less than 70% so so inventor claim is wrong

3 0
3 years ago
The __________________ refers to the main screen of the computer.
Sedbober [7]

Answer:

<em>D</em><em>e</em><em>s</em><em>k</em><em>t</em><em>o</em><em>p</em>

Explain:

<em>Desktop refers to the main screen of the computer. It is the first screen you see after logging in. The desktop’s appearance can vary widely because it is highly customizable, but generally desktops will feature a large image, icons, and a taskbar(covered later on this page).</em>

4 0
2 years ago
50.38
klemol [59]

Answer:

International Building Code (IBC)

Explanation:

6 0
2 years ago
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