Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
If the circumference of a circle is changed from 9 cm to 3 cm, then the diameter decreases by a factor of 3.
Lets say the base is x and the height is y. The new base would be 1.2x and the new height would be 1.3y
Area of a triangle is base times height divided by 2:
1.2x*1.3y/2 = (1.2*1.3 + x*y)/2 = 1.56xy/2 = 0.78xy = 78% of xy
But a normal area would be 50% of xy
78% - 50% = 38%
ANSWER: 38% increase
This might not be correct but....
I’m going to use rounding,
42 x 2 = 84
84 divides by 3 = 28,
Which is near 30......So the number of people in the group is rounding to about 2 people.
Based on the above:
The slope of P'Q' is = -3/2
The length of P'Q' is approximately = ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
<h3>What is the polygon about?</h3>
The slope of P'Q'
= -6/4 = -3/2
The length of P'Q' =
P'Q' = 
= 
= ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
Therefore;
P'Q' =
P'Q' =
x ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
= ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
Learn more about polygon from
brainly.com/question/1592456
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