Ask question

Ask question

All categories

3 years ago

12

What school objects in a class have organic compounds

1 answer:

Elenna [48]3 years ago

4 0

mostly anything

like wood carpet

You might be interested in

Identity which statement is true:

Anvisha [2.4K]

Ans :C
same proton(atomic no.) and electron, diff neutrons
mass no= electrons + neutrons

8 0

4 years ago

Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2

Salsk061 [2.6K]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

$2C(s)+2H_2(g)\rightarrow C_2H_4(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_1=-393.7kJ$ ( × 2)

(2) $H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_2=-285.9kJ$ ( × 2)

(3) $2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$ $\Delta H_3=-1411kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is 51.8 kJ.

6 0

4 years ago

Iodine solution is used to test for

ZanzabumX [31]

Answer:

The answer is starch

HAVE A NICE DAY

6 0

3 years ago

A ball was kicked by a player, the ball was stationary, then it gains a velocity of 5 m/s North. Did the ball accelerate or no?

Tomtit [17]

Answer:

yes

Explanation:

it started moving North 5 m/s

7 0

3 years ago

A 5.00 cm^3 sample of gold has a mass of 96.5 g. Calculate the density of gold.

Sholpan [36]

Answer:

$\boxed {\boxed {\sf 19.3 \ g/cm^3}}$

Explanation:

We are asked to calculate the density of gold. The density of a substance is its mass per unit volume. It is calculated using the following formula.

$\rho= \frac{m}{v}$

The mass of the sample is 96.5 grams. The volume of the sample is 5.00 cubic centimeters.

m= 96.5 g
v= 5.00 cm³

Substitute the values into the formula.

$\rho= \frac{ 96.5 \ g}{5.00 \ cm^3}$

Divide.

$\rho= 19.3 \ g/cm^3$

The density of gold is <u>19.3 grams per cubic centimeter.</u>

8 0

3 years ago