Answer:
P = 58.52 atm
Explanation:
Given data:
Mass of sample = 32.0 g
Pressure of sample = ?
Volume of gas = 850 cm³
Temperature of gas = 30°C
Solution:
Number of moles of gas:
Number of moles = mass/molar mass
Number of moles = 32.0 g/ 16 g/mol
Number of moles = 2 mol
Pressure of gas:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
850 cm³ × 1L /1000 cm³ = 0.85 L
by putting values,
P× 0.85 L = 2 mol × 0.0821 atm.L/ mol.K × 303 K
P = 49.75 atm.L/ 0.85 L
P = 58.52 atm
Answer:
Explanation:
Assumptions
- They would ionize completely, or you must assume that.
- The volumes must be the same as well.
- 0.11M Cu(NO3)2 ===> 0.11MCu2+ + 0.22 NO3-
Note
The concentrations would merely add. All things change if the assumptions I've made are not true.
CaCO3 is the reactant in excess. The amount of CaCO3 remaining is 11.5 g . ... Hydrochloric acid and calcium chloride. 2 mol HCl1 CaCl2. Determine the mass of CaCO3 that reacted with the limiting reactant HCl .
Answer:
it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma
