Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Answer:
<u>The acceleration is 0.0012 meters/seconds²</u>
Step-by-step explanation:
1. Let's review the information given to answer the question correctly:
Mass = 250,000 kg
Force = 300 Newtons
2. What is the acceleration?
Based on Newton's Second Law of Motion, let's recall that:
Force = Mass * Acceleration
Acceleration = Force/Mass
Replacing with the real values, we have:
Acceleration = 300/250,0000
Acceleration = 0.0012 meters/seconds² (we can't express acceleration using Newtons/kilograms as the unit).
What is ?
there isn’t a picture
Answer:
625 seconds and 10 minutes
Step-by-step explanation:
distancs=S=5km=5000m
average speed=v=8m/s
time taken=t=?
as we know that
average speed=
average speed×time taken=distance covered
here we have to find the time taken
time taken=
time taken=
time taken=625seconds
now we convert seconds into minutes
10 minutes
