Answer:
W = 600 J
Explanation:
We have,
According to attached figure,
Height of the inclined plane is 60 m
Force acting on the block is 10 N
It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :
W = mgh
or
So, the work done against the gravity is 600 J.
If resistors are connected in series then total resistance=2+2+2+2+2
=10 watt
if connected in parallel then total resistance,1/R=1/2+1/2+1/2+1/2+1/2
1/R=5/2
So R=2/5
R=0.4w
Answer:
Your answer will be C. 3.8 kPa.
The inverse hyperbolic cosecant of anything is a negative number.
In particular, csch⁻¹ [ (-1)/(2√30) ] = csch⁻¹ (≈ -0.0913) = ≈ -3.089
Whatever it is, negative numbers don't have logarithms.
