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Goryan [66]
3 years ago
14

(WILL GIVE BRAINLIEST ANSWER) A runner burns 10 kilocalories per minute. If the runner completes a race in 1 hour and ten minute

s, how many kilocalories does he burn during the entire race? How many grams of pasta would provide him with this much energy? (1 gram of pasta gives 4.06 kilocalories of energy)
Chemistry
2 answers:
Vadim26 [7]3 years ago
7 0
60 minutes in an hour so. 60 times 10=600+10 more minutes

He burns 610 kilocalories

Then 610 / 4.06

150.25
yulyashka [42]3 years ago
4 0

Answer:

700 kilo calories was burnt during the entire race.

172.41 grams of pasta would provide him with 700 kcal energy.

Explanation:

Rate of burning calories = R = 10 kcal/min

Number of calories burnt in 1 hour and 10 minutes = x

Duration of race = t =  1 hour + 10 min

1 hour = 60 minutes

t = 60 min + 10 min = 70 min

x=R\times t=10 kcal/min\times 70 min=700 kcal

700 kilo calories was burnt during the entire race.

Number of calories in 1 gram of pasta = 4.06 kcal/g

Amount of pasta with 700 kcal = m

m\times 4.06 kcal/g=700 kcal

m=\frac{700 kcal}{4.06 kcal/g}=172.41 g

172.41 grams of pasta would provide him with 700 kcal energy.

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<h3><u>Answer;</u></h3>

Acids;  HCl and HC5H5N+

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<h3><u>Explanation;</u></h3>
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How many kilojoules (KJ) in 3.58 x 10^4 Calories?
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Answer:

The answer to your question is: letter B

Explanation:

Data

3.58 x 10⁴ cal to joules

                                  1 calories ---------------  4.184 joules

                                   3.58 x 10⁴ cal-----------    x

                                   x = (  3.58 x 10⁴ x 4.184) / 1

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Answer:

C = 18.29 g  

Explanation:

Given data:

Mass of beryllium needed = ?

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Solution:

Chemical equation:

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now we will calculate the number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 18.9 g/ 28 g/mol

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Now we will compare the moles of nitrogen and Be from balance chemical equation.

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                       1          :       3

                  0.675       :      3/1×0.675 = 2.03 mol

Number of moles of Be needed are 2.03 mol.

Mass of Beryllium:

Mass = number of moles × molar mass

Mass = 2.03 mol ×   9.01 g/mol

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