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Westkost [7]
2 years ago
6

Could someone please HELP ME

Chemistry
1 answer:
scoundrel [369]2 years ago
8 0

a) chemical energy

b) by electricity

c)

(i) Light

(ii) thermal transfer

<em>By </em><em>Benjemin</em>

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A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the<br> temperature of the gas?
lara [203]

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

7 0
3 years ago
Relative dating determines the relative age of fossils according to
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The answer Is C.the layer of rock they're found in
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2 years ago
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Match the salt with the acid and base used to form it in a neutralizing reaction. K2SO4
emmasim [6.3K]

Answer:

KOH and H₂SO₄

Explanation:

Neutralization reaction:

It is the reaction in which acid and base react with each other and produce salt and water.

For example:

2KOH + H₂SO₄  →   K₂SO₄ + 2H₂O

1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

2. Potassium hydroxide and phosphoric acid react to produce potassium phosphate and water.

H₃PO₄  + 3KOH  → K₃PO₄ + 3H₂O

3. Phosphoric acid sodium hydroxide react to produce sodium phosphate and water.

H₃PO₄  + 3NaOH   → Na₃PO₄ + 3H₂O

3 0
3 years ago
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CO<br> +<br> -<br> 02<br> CO2<br> Balance the equation
poizon [28]

Answer:

2co+o2=2co2

Explanation:

co+o2=co2

here is one carbon monoxide and two oxygen react with it and forms carbon dioxide..

2co+o2=2co2

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5 0
2 years ago
A sample of paper from an ancient scroll was found to contain 39.5% 14C content as compared to a present-day sample. The t1/2 fo
nirvana33 [79]

Answer

7665 years

Procedure

Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:

N = N₀e^(-λt)

where λ is the decay constant which is related to half-life (T1/2) by the equation:

\lambda=\frac{ln(2)}{t_{\frac{1}{2}}}

Here, ln(2) is the natural logarithm of 2.

The percent of carbon-14 remaining after time t is given by N/N₀.

Using the first equation, we can determine λt.

The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

\lambda=\frac{ln(2)}{5720}=1.211\times10^{-4}

Solving the second equation for t, and using the λ we have just calculated we will have

t= 7665 years

3 0
8 months ago
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