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Westkost [7]
2 years ago
6

Could someone please HELP ME

Chemistry
1 answer:
scoundrel [369]2 years ago
8 0

a) chemical energy

b) by electricity

c)

(i) Light

(ii) thermal transfer

<em>By </em><em>Benjemin</em>

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A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t
VashaNatasha [74]

Answer: V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{T_1P_2}

where,

P_1 = initial pressure of gas = 101.3 kPa

P_2 = final pressure of gas = 94.6 kPa

V_1 = initial volume of gas = 20.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 297K

T_2 = final temperature of gas = 283K

Now put all the given values in the above equation, we get the final volume of gas.

V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

V_2=20.4ml

Thus the correct numerical setup for calculating the new volume is \frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

3 0
3 years ago
There are 55.0 g of neon gas in a 3.0 L cylinder, the pressure is 4.5 atm what is the temp of the gas
marshall27 [118]

Answer:

60.9 Kelvin

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Pressure (P)= 4.5 atm

Volume (V)= 3L

Number of Moles (n)= ?

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We don't have all the information we need to plug the values into the equation. We still need to know how many moles 55.0 grans of neon is.

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Now that we have all the information we need, plug everying into the equation. In case you don't know, the Ideal Gas Law Equation is PV= nRT.

(4.5)(3) = (2.7)(0.821)x    

x= 60.9

Now you have your temperature! It is 60.9 in Kelvin.

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