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LUCKY_DIMON [66]
3 years ago
13

Calculate the percent error of the distance to the moon.

Physics
1 answer:
Bess [88]3 years ago
3 0

Answer:

Explanation:

Difference in the measurement by shuttle crew  Δ d = 238857 - 226316 miles

= 12541 miles

Actual measurement =  238857 miles

percentage error

= (12541 / 238857 ) x 100

= 5.25 %

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Natali5045456 [20]
1. Life
2. Your grades at school
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PLZ HELP DUE IN 10 MINUTES
likoan [24]

Answer:50%

Explanation: put it you are in a hurry

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3 years ago
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
3 years ago
Forces cause changes to the motion of objects. Name a force and describe two changes it makes.
otez555 [7]
Sliding and Static.

Would be the right one here.
3 0
4 years ago
Help for physics
12345 [234]

Answer:

A. 5 m/s

Explanation:

From the graph, for the first 2 seconds, the graph is a straight line meaning that the slope is a constant.

Average speed of an object is the rate of change of position. Here, the position of the object changes from 0 m to 10 m for a time interval of 2 seconds.

The change in position (\Delta x) and time interval (\Delta t) are given as:

\Delta x=10-0=10\ m\\\Delta t=2-0=2\ s

Therefore, the average speed (s_{avg}) is given as the ratio of the total change in position and the time interval for the change.

s_{avg}=\frac{\Delta x}{\Delta t}=\frac{10-0}{2-0}=\frac{10}{2}=5\ m/s

Hence, the average speed is 5 m/s.

8 0
3 years ago
Read 2 more answers
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