Answer: Question 1: Efficiency is 0.6944
Question 2: speed of similar pump is 2067rpm
Explanation:
Question 1:
Flow rate of pump 1 (Q1) = 300gpm
Flow rate of pump 2 (Q2) = 400gpm
Head of pump (H)= 55ft
Speed of pump1 (v1)= 1500rpm
Speed of pump2(v2) = ?
Diameter of impeller in pump 1= 15.5in = 0.3937m
Diameter of impeller in pump 2= 15in = 0.381
B.H.P= 6.0
Assuming cold water, S.G = 1.0
eff= (H x Q x S.G)/ 3960 x B.H.P
= (55x 300x 1)/3960x 6
= 0.6944
Question 2:
Q = A x V. (1)
A1 x v1 = A2 x V2. (2)
Since A1 = A2 = A ( since they are geometrically similar
A = Q1/V1 = Q2/V2. (3)
V1(m/s) = r x 2π x N(rpm)/60
= (0.3937x 2 x π x 1500)/2x 60
= 30.925m/s
Using equation (3)
V2 = (400 x 30.925)/300
= 41.2335m/s
To rpm:
N(rpm) = (60 x V(m/s))/2 x π x r
= (60 x 41.2335)/ 2× π × 0.1905
= 2067rpm.
Momentum is Mass × Velocity
= 1875×22 = 41250 kg m/sec
Answer:
There should be a total voltage of zero (0)
Explanation:
In bipolar encoding (multilevel binary), there are three voltage levels, positive, negative, and zero. The voltage level for one data element is at zero, while the voltage level for the other element alternates between positive and negative.
However, the primary advantage of a bipolar scheme is that when all the voltages are added together after a long transmission, there should be a total voltage of zero.
Answer:
When the radius is doubled, its speed will be 42.42 km/h.
Explanation:
Given that,
The maximum speed around a level curve is 30 km/h = 8.34 m/s
We need to find the maximum speed around a curve with twice the radius. The maximum speed of the object is given by :
............(1)
If radius is doubled, r' = 2r
The maximum speed is given by :

..........(2)
Dividing equation (1) and (2) we get :



v' = 42.42 km/h
So, when the radius is doubled, its speed will be 42.42 km/h. Hence, this is the required solution.