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3 years ago

Compare the earths climate today with its climate during an ice age.

Physics

1 answer:

tresset_1 [31]3 years ago

5 0

It’s a lot warmer now
Than it is during an ice age

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If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?

yaroslaw [1]

Answer:

735watts

Explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

Power = 1470/2

Power = 735Watts

Hence the minimum power output is 735watts

7 0

3 years ago

A small car of mass m and a large car of mass 4m drive along a highway at constant speeds VS and VL. They approach a curve of ra

Arte-miy333 [17]

Answer:

$v_S=\sqrt{2}v_L$

Explanation:

The acceleration experimented while taking a curve is the centripetal acceleration $a=\frac{v^2}{r}$ . Since $a_S=2a_L$ , we have that: $\frac{v_S^2}{r_S}=\frac{2v_L^2}{r_L}$

They take the same curve, so we have: $r_S=r_L=R$

Which means: $v_S^2=2v_L^2$

And finally we obtain: $v_S=\sqrt{2}v_L$

4 0

3 years ago

A diver rises quickly to the surface from a 5.0 m depth. If she did not exhale the gas from her lunds before rising, by what fac

Inessa [10]

Answer:

1.5 times

Explanation:

$h$ = depth of the diver initially = 5 m

$\rho$ = density of seawater = 1030 kg m⁻³

$P_{i}$ = Initial pressure at the depth

$P_{f}$ = final pressure after rising = 101325 Pa

Initial pressure at the depth is given as

$P_{i} = P_{f} + \rho gh\\P_{i} = 101325 + (1030) (9.8) (5)\\P_{i} = 151795 Pa$

$V_{i}$ = Initial volume at the depth

$V_{f}$ = Final volume after rising

Since the temperature remains constant, we have

$P_{f} V_{f} = P_{i} V_{i}\\(101325) V_{f} = (151795) V_{i}\\V_{f} = 1.5 V_{i}$

6 0

3 years ago

The planet Krypton has a mass of 7.6 × 1023 kg and radius of 1.7 × 106 m. What is the acceleration of an object in free fall nea

olga55 [171]

Answer:

17.55 m/s²

Explanation:

Parameters given:

Mass of Krypton, M = 7.6 * 10^23 kg

Radius, R = 1.7 * 10^6 m

Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²

Acceleration due to gravity of planet of mass M is given as:

g = GM/R²

Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.

Therefore,

g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²

g = 17.55 m/s²

5 0

3 years ago

A -0.00325 C charge q1 is placed 5.62 m from a second charge q2. The first charge is repelled with a 48900 N force. What is the

blagie [28]

Answer: q2 = -0.05286

Explanation:

Given that

Charge q1 = - 0.00325C

Electric force F = 48900N

The electric field strength experienced by the charge will be force per unit charge. That is

E = F/q

Substitute F and q into the formula

E = 48900/0.00325

E = 15046153.85 N/C

The value of the repelled second charge will be achieved by using the formula

E = kq/d^2

Where the value of constant

k = 8.99×10^9Nm^2/C^2

d = 5.62m

Substitutes E, d and k into the formula

15046153.85 = 8.99×10^9q/5.62^2

15046153.85 = 284634186.5q

Make q the subject of formula

q2 = 15046153.85/ 28463416.5

q2 = 0.05286

Since they repelled each other, q2 will be negative. Therefore,

q2 = -0.05286

6 0

3 years ago