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Gnom [1K]
3 years ago
14

A circle has a circumference of 10. It has an arc length of 9/2. What is the central angle of the arc in degrees?

Mathematics
2 answers:
ki77a [65]3 years ago
8 0

Answer:

162 degrees

Step-by-step explanation:

1 / 6

The ratio between the arc's central angle θ (theta) and 360° is equal to the ratio between the arc length (s) and the circle's circumference (c).

2/6

\frac{theta}{360 degrees}  = \frac{s}{c}

3/6

\frac{theta}{360degrees}  = \frac{9}{2} ÷ 10

4/6

\frac{theta}{360degrees}  =\frac{9}{20}

5/6

θ = \frac{9}{20} × 360°

6/6

θ = 162°

dem82 [27]3 years ago
6 0

Answer: The central angle of the arc is 162 degrees.

Step-by-step explanation: The information available are as follows;

Circumference of the circle equals 10. Length of an arc equals 9/2. The circumference of a circle is given as;

Circumference = 2Pi x r

That means 2Pi x r = 10.

Also the length of an arc along the same circle is 9/2. Length of an arc is calculated as;

Length of arc = (X/360) x 2Pi x r

Where X is the central angle of the arc

That means;

9/2 = (X/360) x 2Pi x r

We can now substitute for the known values as follows

Length of an arc = (X/360) x 2Pi x r

9/2 = (X/360) x 10

9/2 = 10X/360

By cross multiplication we now have

(9 x 360)/(2 x 10) = X

3240/20 = X

162 = X

The angle at the center of the arc is 162 degrees.

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Which method is not used to find the solution of a system of linear equations. guess and checkA. graphingB. substitutionC. matri
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F(x)=-3x+21,find x when f(x)=6
balu736 [363]

Answer:

x=5

Step-by-step explanation:

F(x)=-3x+21,

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6 0
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Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
Sloan [31]

\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
3 years ago
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