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2 years ago

An object appears red when viewed with white light. What color would it appear when viewed with blue light?

2 answers:

8 0

The colour of an object depends upon the light reflected and absorbed, so if you the object appears blue to you that means that the object reflects blue light and absorbs rest of the spectrum. That's why in black colour all light is absorbed and no light is emitted, thus absorbing all the radiation heat. Now, coming to the point, the red light incident on the object will contain light composed of many wavelength, some of which will be reflected by the body, so the body should reflected light of wavelength near to blue light thus giving a darkish red, with blueish tint. The resultant should be somewhat dark maroon.

zvonat [6]2 years ago

7 0

Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

Explanation:

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2 years ago

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Answer:

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Explanation:

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3 years ago

If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. It i

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Answer:

a.0.120mm

b.1.58s

c.0.6329Hz

Explanation:

a. Given that 0.120mm is displaced from equilibrium, 0.120mm after 0.790s on opposite side:

-The amplitude is the maximum displacement from equilibrium.

-The object goes from x=+A to x=-A and back during one cycle.

#Hence, the amplitude of the motion is 0.120mm

b.Motion from maximum positive displacement to maximum negative displacement takes places during half the period of Simple Harmonic Motion(SHM)

$0.790s=T/2\\\\T=0.790s\times 2\\\\T=1.58s$

#Hence, the period of the motion is 1.58s

c. Frequency is calculated as one divided by the period of the motion.

From b above we know that the motions period is 1.58s

Therefore:

Frequency=1/period=1/1.58=0.6329Hz

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2 years ago

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3 years ago

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Answer : The average value of current is $1.0\times 10^2\ A$ .