An object appears red when viewed with white light. What color would it appear when viewed with blue light?

2 answers:

8 0

The colour of an object depends upon the light reflected and absorbed, so if you the object appears blue to you that means that the object reflects blue light and absorbs rest of the spectrum. That's why in black colour all light is absorbed and no light is emitted, thus absorbing all the radiation heat. Now, coming to the point, the red light incident on the object will contain light composed of many wavelength, some of which will be reflected by the body, so the body should reflected light of wavelength near to blue light thus giving a darkish red, with blueish tint. The resultant should be somewhat dark maroon.

zvonat [6]3 years ago

7 0

Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

Explanation:

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A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?

ludmilkaskok [199]

The answer is 24.84kJ.

We apply the expression for the work done by the heat engine is,

$W=E_{i n}-E_{o u t}$ . Putting all given values in the equation we get the final answer.

What is heat engine?

A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$ . The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$ .
The expression for the work done by the heat engine is, $W=E_{i n}-E_{o u t}$
Substituting the given values in the above expression, we will get $W =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}$ =24.84kJ.
Thus, the work done by the heat engine is 24.84kJ.