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zheka24 [161]
3 years ago
14

A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of

the car in m/s2?
Physics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

Acceleration of the car will be a=8m/sec^2

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that s=ut+\frac{1}{2}at^2

So 400=0\times 10+\frac{1}{2}\times a\times 10^2

a=8m/sec^2

So acceleration of the car will be a=8m/sec^2

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A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit
Aloiza [94]

Answer:

0.04328 H

0.00288 seconds

0.01326 seconds

Explanation:

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I = Decayed current = 0.21 A

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Maximum Current is given by

I_0=\frac{V}{R}\\\Rightarrow I_0=\frac{6.3}{15}\\\Rightarrow I_0=0.42\ A

Current in the circuit is given by

I=I_0exp\frac{-Rt}{L}\\\Rightarrow ln\frac{I_0}{I}=\frac{Rt}{L}\\\Rightarrow L=\frac{Rt}{ln\frac{I_0}{I}}\\\Rightarrow L=\frac{15\times 2\times 10^{-3}}{ln\frac{0.42}{0.21}}\\\Rightarrow L=0.04328\ H

The inductance is 0.04328 H

Time constant is given by

\tau=\frac{L}{R}\\\Rightarrow \tau=\frac{0.04328}{15}\\\Rightarrow \tau=0.00288\ s

Time constant is 0.00288 seconds

Time required is given by

t=\tau ln\frac{I_0}{I}\\\Rightarrow t=0.00288\times ln\frac{I_0}{0.01I_0}\\\Rightarrow t=0.01326\ s

The time to reach 1% of its original value is 0.01326 seconds

7 0
4 years ago
When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compar
dalvyx [7]

Answer:

The question was incomplete. Here is the complete question.

Explanation:

A helium-filled balloon escapes a child’s hand at sea level and 20.0C. When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compare to that at sea level?

The ideal gas equation:

PV = nRT

P = absolute pressure

V = Volume of a gas

n = no of moles of a gas

R = ideal gas constant

T = Absolute temperature of a gas

For initial and final states:

P_{i}V_{i} = nRT_{i}   \\P_{f}V_{f} = nRT_{f}   \\\frac{V_{f} }{V_{i} } = \frac{P_{i}T_{f} }{P_{f}T_{i} }

= 1.4

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