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zheka24 [161]
3 years ago
14

A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of

the car in m/s2?
Physics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

Acceleration of the car will be a=8m/sec^2

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that s=ut+\frac{1}{2}at^2

So 400=0\times 10+\frac{1}{2}\times a\times 10^2

a=8m/sec^2

So acceleration of the car will be a=8m/sec^2

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3 years ago
A force of 200N acts between two objects at a certain distance apart .the value of the force when the distance is halved is?
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Answer:

800N is the answer

Explanation:

hope it helps

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2 years ago
michael kicks a ball at an angle if 36* horizontal. its initial velocity is 46 m/s. Find the maximum height it can reach, total
MAVERICK [17]

(a) At its maximum height, the ball's vertical velocity is 0. Recall that

{v_y}^2-{v_{0y}}^2=2a_y\Delta y

Then at the maximum height \Delta y=y_{\mathrm{max}}, we have

-\left(\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

\implies y_{\mathrm{max}}=37\,\mathrm m

(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

v_y=v_{0y}+a_yt

and at its maximum height, v_y=0 so that

0=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ+\left(-9.8\,\dfrac{\mathrm m}{\mathrm s}\right)t

\implies t=2.8\,\mathrm s

which would mean the ball spends a total of about 5.6 seconds in the air.

(c) The ball's horizontal position in the air is given by

x=v_{0x}t

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x=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\cos36^\circ(5.6\,\mathrm s)

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3 years ago
To pull a 53 kg crate across a horizontal frictionless floor, a worker applies a force of 180 N, directed 35° above the horizont
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Answer

given,

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crate moves = 2.9 m

a) The work done equals the force in the direction of the displacement, times the displacement

W = F_x ×d

W = 180 cos 35° × 2.9

W = 427.6 J

b) A force that is perpendicular to the direction of the displacement does not do any work so work done by gravitational force is zero

c) Similarly for the normal force the work done will be zero.

d) Total work done by the crate is equal to 427.6 J

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3 years ago
Look at the diagram showing resistance and flow of electrons. A top box labeled X contains 2 circles with plus signs and 2 circl
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Answer:

D: X: Low potential energy

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Explanation: trust

3 0
3 years ago
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