Answer:
Adding H₂O(g) to the system.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
<u><em>1) Removing H₂O(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of H₂O(g) from the system.
<u><em>2) Adding CH₃CHO(g) to the system :</em></u>
- This will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the adding CH₃CHO(g) to the system.
<u><em>3) Removing C₂H₂(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of C₂H₂(g) from the system.
<u><em>4) Adding H₂O(g) to the system:</em></u>
- This will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the addition of H₂O(g) to the system.
- <u><em>So, it is the right choice.</em></u>
A. is the correct answer.
Answer:
0.382g
Explanation:
Step 1: Write the reduction half-reaction
Al³⁺(aq) + 3 e⁻ ⇒ Al(s)
Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s
We will use the following relationships.
- 1 mole of electrons has a charge of 96486 C (Faraday's constant)
- 1 mole of Al is produced when 3 moles of electrons pass through the cell.
- The molar mass of Al is 26.98 g/mol.
The mass of Al produced is:
