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Delvig [45]
3 years ago
8

What happens in nuclear fusion?

Chemistry
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

The correct answer is option B.

Explanation:

Nuclear fusion is a nuclear process in which two small nuclei combines together to form a heavy nuclei along with release of large amount of energy.

Nuclear fission is a nuclear process in which heavier nuclei splits into two or more small and stable nuclei along with the release of large amount of energy.

From the given options the apt option explaining nuclear fusion is option B.

vfiekz [6]3 years ago
5 0
The answer is B particles combine into a large amount of engery.
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How many grams of precipitate will be formed when 20.5 mL of 0.800 M
Anton [14]

Answer:

There will be formed 1.84 grams of precipitate (NaNO3)

Explanation:

<u>Step 1</u>: The balanced equation

CO(NO3)2 (aq) + 2 NaOH (aq) → CO(OH)2 (s) + 2 NaNO3 (aq)

<u>Step 2:</u> Data given

Volume of 0.800 M  CO(NO3)2 = 20.5 mL = 0.0205 L

Volume of 0.800 M NaOH = 27.0 mL = 0.027 L

Molar mass of NaNO3 = 84.99 g/mol

<u>Step 3:</u> Calculate moles of CO(NO3)2

Moles CO(NO3)2  = Molarity * volume

Moles CO(NO3)2  = 0.800 M * 0.0205

Moles CO(NO3)2 = 0.0164 moles

Step 4: Calculate moles NaOH

moles of NaOH = 0.800 M * 0.027 L

moles NaOH = 0.0216 moles

Step 5: Calculate limiting reactant

For 1 mole CO(NO3)2 consumed, we need 2 moles of NaOH to produce 1 mole of CO(OH)2 and 2 moles of NaNO3

NaOH is the limiting reactant. It will completely be consumed.

CO(NO3)2 is in excess. There willbe 0.0216 / 2 = 0.0108 moles of CO(NO3)2 consumed. There will remain 0.0164 - 0.0108 = 0.0056 moles of CO(OH)2

Step  6: Calculate moles of NaNO3

For 2 moles of NaOH consumed, we have 2 moles of NaNO3

For 0.0216 moles of NaOH, we have 0.0216 moles of NaNO3

Step 7: Calculate mass of NaNO3

mass of NaNO3 = moles of NaNO3 * Molar mass of NaNO3

mass of NaNO3 = 0.0216 moles * 84.99 g/mol = 1.84 grams

There will be formed 1.84 grams of precipitate (NaNO3)

5 0
2 years ago
An atom has the following electron configuration 1s2s2sp63s23p64s2 How many valance electrons does this atom have?
JulijaS [17]

Answer:

The electron configuration for this atom is Calcium, which has 2 valence electrons.

Explanation:

Following the periodic table and with the electron configuration, you will end up with calcium, which has 2 valence electrons. (Always follow the electron configuration from left to right! It begins at hydrogen, then to helium... and so on.)

1s2 -> He....

2s2 -> Be....

2p6 -> Ne...

3s2 -> Mg...

3p6 -> Ar...

4s2 -> Ca.

6 0
3 years ago
After substantial heating, 6.25 g of iron produced 18.00 g of a compound with chlorine. The empirical formula is:
babunello [35]

Answer:

Option A. FeCl3

Explanation:

The following data were obtained from the question:

Mass of iron (Fe) = 6.25g

Mass of the compound formed = 18g

From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow

Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.

Mass of chlorine (Cl) = 18 – 6.25

Mass of chlorine (Cl) = 11.75g

The compound therefore contains:

Iron (Fe) = 6.25g

Chlorine (Cl) = 11.75g

The empirical formula for the compound can be obtained by doing the following:

Step 1:

Divide by their molar mass

Fe = 6.25/56 = 0.112

Cl = 11.75/35.5 = 0.331

Step 2:

Divide by the smallest

Fe = 0.112/0.112 = 1

Cl = 0.331/0.112 = 3

The empirical formula for the compound is FeCl3

3 0
3 years ago
Need help ASAP please show your work
VikaD [51]

Answer:

q = 14049 J

Explanation:

q = m*c*(t2-t1)

q = 350 * 0.892 * (70-25) =

312.2 * 45 = 14049 J

I might be getting a little confused but I could be right.

Hope this helps!

4 0
2 years ago
a chemist wishes to mix some pure acid with some water to produce 16L of a solution that is 30% acid how much pure acid and how
Aloiza [94]

<u>Answer:</u> The volume of acid and water that must be mixed will be 4.8 L and 11.2 L

<u>Explanation:</u>

We are given:

Volume of mixture = 16 L

Percent of acid present = 30 %

Calculating the percentage of acid present in the mixture:

\Rightarrow 16\times \frac{30}{100}=4.8L

The mixture is made entirely of acid and water.

Volume of acid in the mixture = 4.8 L

Volume of water in the mixture = 16 - 4.8 = 11.2 L

Hence, the volume of acid and water that must be mixed will be 4.8 L and 11.2 L

4 0
3 years ago
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