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sergey [27]
4 years ago
8

32 POINTS!!!!

Chemistry
2 answers:
krok68 [10]4 years ago
8 0
1. statement
2. b
3. a
makkiz [27]4 years ago
3 0
I think your answer are A B A
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What is the number of moles of solute in 250 mL of a .80M solution
Illusion [34]

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution

Explanation:

because it is

8 0
3 years ago
A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a ve
morpeh [17]
The kinetic energy of a moving object is calculated through the equation,
                                 KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,
                                KE = 0.5(55 kg)(16 m/s)²
                                KE = 7,040 J
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4 0
3 years ago
Read 2 more answers
Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th
Black_prince [1.1K]

Answer:

K_{goal}=1.793*10^{-33}

Explanation:

N2(g)+O2(g)⇌2NO(g), K_1 = 4.10*10^{-31}

N2(g)+2H2(g)⇌N2H4(g), K_2 = 7.40*10^{-26}

2H2O(g)⇌2H2(g)+O2(g), K_3 = 1.06*10^{-10}

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g)                     Eq (1)

Equilibrium constant for Eq (1) is K_1*K_3*K_3

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g)                       Eq (2)  

Equilibrium constant for Eq (2) is (K_1*K_3*K_3)^{1/2}

Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}

7 0
3 years ago
Which of the following statements is not correct?
deff fn [24]
<span>C. More than two electrons can be transferred in ionic bonds or shared in covalent bonds.</span>
6 0
4 years ago
Which of the following is the primary medium for beach erosion?
Rus_ich [418]

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Water is the primary erosion

hope it helps :)

3 0
4 years ago
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