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sergey [27]
4 years ago
8

32 POINTS!!!!

Chemistry
2 answers:
krok68 [10]4 years ago
8 0
1. statement
2. b
3. a
makkiz [27]4 years ago
3 0
I think your answer are A B A
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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

8 0
3 years ago
Most immigrants from the 1820 to 1850 came from which two countries? France and the United Kingdom Ireland and Germany Ireland a
Vera_Pavlovna [14]
Ireland and germany!!
5 0
4 years ago
Read 2 more answers
A student was trying to determine the mole percent of A in a mixture of A and B using refractive index. If their mixture has a r
Elina [12.6K]

Explanation:

Formula to calculate refractive index of n is as follows.

     n = X_{A} \times n_{A} + X_{B} \times n_{B}

where,    X_{A} = mole fraction of A

              X_{B} = mole fraction of B

              n_{A} = refractive index of A

              n_{B} = refractive index of B

Hence, putting the given values into the above formula as follows.

         n = X_{A} \times n_{A} + X_{B} \times n_{B}

         1.5248 = X_{A} \times 1.7058 + X_{B} \times 1.3658 ........ (1)

Also, it is known that X_{A} + X_{B} = 1

and,          X_{B} = 1 - X_{A} ......... (2)

Now, put equation (2) in equation (1) as follows.

        1.5248 = X_{A} \times 1.7058 + 1 - X_{A} \times 1.3658  

        1.5248 = X_{A} \times 1.7058 + 1.3658 - 1.3658X_{A}  

         X_{A} = 0.467

And, the value of  X_{B} is calculated as follows.

            X_{B} = 1 - X_{A}

                       = 1 - 0.467

                       = 0.533

Hence, mole percentage of A will be calculated as follows.

      Mole % of A = \frac{n_{A}}{n_{A} + n_{B}}      

                            = \frac{0.467}{0.467 + 0.533} \times 100

                            = 46.7%

Thus, we can conclude that the mole percent of A in their mixture is 46.7%.

8 0
3 years ago
Ahmed makes a Venn diagram to compare active transport and passive transport across the cell membrane.
lyudmila [28]

Answer:

The labels are not given to represent but the correct answer would be one of these:

-Uses energy

- low concentration to high concentration movement

Explanation:

Active transport and passive transport both are transport methods of the molecules and substances in or out of the cell through the cell membrane. Passive and active transport has only one thing which is the movement of the substance through or across the cell membrane.

However, there are differences in these types of diffusion are:

Active Transport                                        Passive Transport

-Uses energy                                                - a form of diffusion

-Moves from low to high concentration    - from high  to low concentration

4 0
3 years ago
HELP ANSWER THIS QUESTION!​
sammy [17]
Answer 3
Ag is displaced By the more reactive al
7 0
3 years ago
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