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3 years ago

If you were designing a lander to work on Mars, where on Earth would you test it? Why?

Physics

1 answer:

Andreas93 [3]3 years ago

7 0

Answer:

Underwater

Explanation:

One of the most important difference between Earth and Mars is the strength of gravity at the surface. In fact, at the Earth's surface, the strength of the gravitational field is

$g_e = 9.81 m/s^2$

Instead, on Mars' surface is only

$g_m = 3.71 m/s^2$

So, much lower than Earth.

In order to test the lander properly, it must be tested in an environment where gravity is lower than its normal value on Earth. This can be done by testing the lander underwater. In fact, when an object is underwater, it experiences an upward force (called buoyancy). The effect of this force is to decrease the "apparent gravity" on the object: in fact, net force on the object is equal to its weight:

F = mg (downward)

So the acceleration is g. However, due to the presence of the buoyancy, the net force on the object is

F = mg - B

So the apparent gravity on the object will be

$a= g -g'$

And therefore, this "trick" allows to test the lander in an environment with lower gravity, so more similar to Mars surface.

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A ball is dropped from an aircraft flying at an altitude of 8,848 meters assuming gravity is 9.8m/s what is the total amount of

Dafna11 [192]

In this question, you're determining the time (t) taken for an object to fall from a distance (d).

The equation to represent this is:
Time equals the square root of 2 times the distance divided by the gravitational force of earth.
In equation from it looks like this (there isn't an icon to represent square root so just pretend like there's a square root there):
t = 2d/g (square-rooted)

d = 8,848m and g = 9.8m/s

Now plug in the information we have:
t = 2 x 8,848m/9.8m/s (square-rooted)

The first step is to multiply 2 times 8,848m:
t = 17,696m/9.8m/s (square-rooted)

Now divide 9.8m/s by 17,696m (note that the two m's (meters) cancels out leaving you with only s (seconds):
t = 1805.72s (square-rooted)

Now for the last step, find the square root of the remaining number:
t = 42.5s

So the time it takes the ball to drop from the height (distance) of 8,848 meters, and falling with the gravitational pull of 9.8 meters per second is 42.5 seconds.

I hope this helps :)

7 0

3 years ago

(???) Is iz allergic to peanut butter jigglys, I JIGGLE IN THE WIND!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Vadim26 [7]

Uh are u okay? G tell ur parents i-

7 0

3 years ago

A -turn rectangular coil with length and width is in a region with its axis initially aligned to a horizontally directed uniform

madam [21]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The maximum emf is $\epsilon_{max}= 26.8 V$

The emf induced at t = 1.00 s is $\epsilon = 24.1V$

The maximum rate of change of magnetic flux is $\frac{d \o}{dt}|_{max} =26.8V$

Explanation:

From the question we are told that

The number of turns is N = 44 turns

The length of the coil is $l = 15.0 cm = \frac{15}{100} = 0.15m$

The width of the coil is $w = 8.50 cm =\frac{8.50}{100} =0.085 m$

The magnetic field is $B = 745 \ mT$

The angular speed is $w = 64.0 rad/s$

Generally the induced emf is mathematically represented as

$\epsilon = \epsilon_{max} sin (wt)$

Where $\epsilon_{max}$ is the maximum induced emf and this is mathematically represented as

$\epsilon_{max} = N\ B\ A\ w$

Where $\o$ is the magnetic flux

N is the number of turns

A is the area of the coil which is mathematically evaluated as

$A = l *w$

Substituting values

$A = 0.15 * 0.085$

$= 0.01275m^2$

substituting values into the equation for maximum induced emf

$\epsilon_{max} = 44* 745 *10^{-3} * 0.01275 * 64.0$

$\epsilon_{max}= 26.8 V$

given that the time t = 1.0sec

substituting values into the equation for induced emf $\epsilon = \epsilon_{max} sin (wt)$

$\epsilon = 26.8 sin (64 * 1)$

$\epsilon = 24.1V$

The maximum induced emf can also be represented mathematically as

$\epsilon_{max} = \frac{d \o}{dt}|_{max}$

Where $\o$ is the magnetic flux and $\frac{d \o}{dt}|_{max}$ is the maximum rate at which magnetic flux changes the value of the maximum rate of change of magnetic flux is

$\frac{d \o}{dt}|_{max} =26.8V$

8 0

3 years ago

What is the primary cause of diffusion?

Lostsunrise [7]

Answer
c). random internal motion of atoms and molecules.

Explanation 
Diffusion is the movement of particles from a region of high concentration to region of low concentration. The rate of diffusion can be increased by increasing amount of temperature but this is not its primary cause. Diffusion is primarily caused by movement of molecules or atoms in a substances. Form the choices given, the correct answer is c. random internal motion of atoms and molecules.

3 0

3 years ago

Read 2 more answers

The tendency for an object at rest to remain at rest

Zarrin [17]

Inertia is the force in play here

7 0

3 years ago