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xz_007 [3.2K]
3 years ago
10

12. A concave lens has a focal length of 10 cm. An object 2.5 cm high is placed 30 cm from the lens. Determine the position and

size of the image. (3)​
Physics
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

I think 9.5

Explanation:

............

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An elevator is being lowered at steadily decreasing speed by a steel cable attached to an electric motor. There is no air resist
shtirl [24]

Answer:

F = W + ma  a> 0

Explanation:

For this exercise let's use Newton's second law

 we assume the upward direction as positive

          F - W = m a

          F = W + ma

          F = m (g + a)

In this case they indicate that the speed is less and less as it goes down, therefore the acceleration must be opposite to the speed, that is, the acceleration is upwards, consequently it is positive

               

We can see that since a> 0 the force F must have greater than the weight of the elevator

6 0
3 years ago
Read 2 more answers
A charge of 12 passes through the filament of a car head lamp bulb in 4 s. what is current?​
Katena32 [7]

Answer:

3 A

Explanation:

current =  \frac{charge}{time}  \\  =  \frac{12}{4}  \\  = 3 \: amperes

3 0
4 years ago
The resistivity of a semiconductor can be modified by adding different amounts of impurities. A rod of semiconducting material o
zavuch27 [327]

Answer:

pp

Explanation:

7 0
3 years ago
Como sacar velocidad final sin tener el tiempo
Serhud [2]
?????????como ??????? No entiendo
5 0
3 years ago
A crate on a motorized cart starts from rest and moves with a constant eastward acceleration ofa= 2.60 m/s^2. A worker assists t
Leona [35]

Answer:

To obtain the power, we first need to find the work made by the force.

1) To calculate the work, we need the next equation:

\int\limits {F} \, dx

So the force is given by the problem so our mission is to find 'dx' in terms of 't'

2) we know that:

\frac{dV}{dt} = a = 2.6

So we have:

v = 2.6t

Then:

\frac{dx}{dt} = V = 2.6t\\ \\dx = 2.6t*dt

3) Finally, we replace everything:

\int\limits^{4.7}_{0} {5.4t*2.6t} \, dt

After some calculation, we have as a result that the work is:

161.9638 J.

4) To calculate the power we need the next equation:

P = \frac{W}{t}

So

P = 161.9638/4.7 = 34.46 W

8 0
3 years ago
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