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2 years ago

What multiplication fact could you use to find a number that can be divided evenly by 8 and by 9?

Mathematics

2 answers:

kondaur [170]2 years ago

7 0

The answer to the problem is 72 because both 8 and 9 can evenly divide.
~~~ Ella~~~

agasfer [191]2 years ago

3 0

72 can be divided by 8 and 9 because if you multiplied 8 and 9 together it is 72

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A coach drives 360 miles at a speed of 60mph how long did the journey take

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Answer:

6 1/2 hours

Step-by-step explanation:

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3 years ago

Find the greatest common factor of 28x^2 16x

Aleks04 [339]

4x (7x +4). The greatest factor is 4x because it comes out of both.

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3 years ago

find the slope of the line containing the points (-1,6) and (3,5) put final.answer in slope-intercept form

Ugo [173]

Given the points (-1,6) and (3,5).

The formula to find the slope is

$m=\frac{y_2-y_1_{}}{x_2-x_1}$

Take

$x_1=-1,y_1=6,x_2=3,y_2=5$

Plug the values into the formula and find the slope.

$\begin{gathered} m=\frac{5-6}{3-(-1)} \\ =\frac{-1}{4} \end{gathered}$

The slope-intercept form is y = mx+b.

Plug the value of m.

$y=-\frac{1}{4}x+b$

ThusConsider the point (-1,6). Substitute -1 for x and for y into the equation.

$\begin{gathered} 6=-\frac{1}{4}(-1)+b \\ =\frac{1}{4}+b \\ b=6-\frac{1}{4} \\ =\frac{23}{4} \end{gathered}$

Thus, the equation of the line in slope intercept form is

$y=-\frac{1}{4}x+\frac{23}{4}$

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10 months ago

Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.

Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]$

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]$

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

$\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒