You swing a bucket full of water in a vertical circle at the end of a rope. The mass of the bucket plus the water is 1.2 kg. The
center of mass of the bucket plus the water moves in a circle of radius 1.4 m. At the instant that the bucket is at the top of the circle, the speed of the bucket is 7.2 m/s. What is the tension in the rope at this instant
2 answers:
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Answer:
1.2 m from the left end
Explanation:
= mass of the person = 90 kg
= mass of friend = 60 kg
= distance of pivot from the person or from the left end
= length of the seesaw board = 3.0 m
= distance of pivot from the friend or from right end = L - r = 3 - r
Using equilibrium of torque about the pivot
Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)