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Lapatulllka [165]
3 years ago
7

Assume that a vaulter is able to carry a vaulting pole while running as fast

Physics
2 answers:
rewona [7]3 years ago
8 0
A,walls
Speleleelelelekeke
Ipatiy [6.2K]3 years ago
8 0

Answer:

5mu = carry a vaulting pole ( 12 m/s) Also

fast

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Instruction
Simora [160]

According to Edge, the answers is

<h3>3100 V</h3>

and

<h3>200v</h3>

4 0
3 years ago
Which of the circuit offers greater resistance to the flow of current 1A or 2A ?
Dafna1 [17]
1 A offers greater resistance
7 0
3 years ago
Read 2 more answers
A vertical spring has a mass hanging from it, which is displaced from the equilibrium position and begins to oscillate. At what
Orlov [11]

Answer:

the object has least potential energy at mean position of the SHM

Explanation:

If a block is connected with a spring and there is no resistive force on the system

In this case the total energy of the system is always conserved and it will change from one form to another form

So here we will say that

Kinetic energy + Potential energy = Total Mechanical energy

As we can say that total energy is conserved so here we have least potential energy when the system has maximum kinetic energy

So here we also know that at mean position of the SHM the system has maximum speed and hence maximum kinetic energy.

So the object has least potential energy at mean position of the SHM

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Charra [1.4K]

Power = Work / time

The work given here is 83J and the time it took to do 83J of work was 3s

So..

Power = 83J / 3s

Power = 27.67 W or 27.7 W

8 0
3 years ago
A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

3 0
3 years ago
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