The crane is used to support the engine, which has a weight of 1200 lb. Draw the shear and moment diagrams of the boom ABC when
it is in the horizontal position.
1 answer:
Answer:
The explanation as follows
Explanation:
To solve this problem, we must make a free body diagram on the ABC element. This free body diagram is inside the attached images, likewise attached is an outline of the exercise which was found performing an internet search.
Then we can find the force of the hydraulic piston in B, and the force at the point of articulation A, making a sum of moments at point A equal to zero.
Now performing a sum of forces equal to zero on the y-axis, we can find the Ay force.
The negative sign in the force (Ay) means that the direction of it is in the opposite direction.
The shear and moment diagrams can be seen in the second attached image.
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Answer:
q = 2,95 10-6 C
Explanation:
The magnetic force on a particle is described by the equation
F = q v x B
Where bold indicate vectors
Let's make the vector product
vxB =
v x B = 1.20 106 [i ^ (4 0.130) - j ^ (3 0.130)]
vx B = 1.20 106 [0.52 i ^ - 0.39j ^]
As they give us the force module, let's use Pythagoras' theorem,
|v xB | =1.20 10⁶ √( 0.52² + 0.39²)
|v x B| = 1.20 10⁶ 0.65
v xB = 0.78 10⁶
Let's replace and calculate
2.30 = q 0.78 10⁶
q = 2.3 / 0.78 106
q = 2,95 10-6 C